Answer:
3rd one is no. the others are all yes
The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.
We want angle x, which is opposite the side of length 39.
Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x
or 1521 = 3481 + 1296 - 2(36)(59) cos x
Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x
-3256 = -4248cos x
-3256
Then: cosx = --------------- = 0.766
-4248
Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)
Well, (m^2-7m-11) ÷ (m-8) = m+1 with a remainder of -3
Answer:
x(3 – 4)
Step-by-step explanation:
x^3y
/x^4y
get rid of y
x^3/x^4
subtract exponents
x(3 – 4)
Brainliest please ask me if you have more questions.
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Step-by-step explanation: