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hichkok12 [17]
3 years ago
5

Through(-3,0)and (0,3)

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

Step-by-step explanation:

the  equation line passes through(-3,0)and (0,3)  is : y=ax+b

a is the slope   a = (3-0)/(0+3) = 1

so : y= x +b  calculate b  line passes through(-3,0)and (0,3)

x=0   y=3  : 3 = 0+b       so  b= 3

this equation is : y= x+3

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Answer: A; r = square root (S/4pi)

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1. Divide 4pi on both sides to get r^2 by itself so the left side becomes S/4pi (you do this because 4, pi, and r^2 are being multiplied together on the right side in the original equation so to cancel that out and get r by itself you do the opposite of multiplication)

The equation should now look like r^2 = S/4pi

2. Square root both sides including r to get rid of the r^2 so it becomes just r (also when you square root both sides, you square root all of S/4pi not just S or 4pi but the whole thing)

After you do that, you get r = square root (S/4pi) which is answer A

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