What’s the answer? (SOMEONE PLEASE HELP)

Lol could someone explain to me the answer and how they got the answer I'm very confused about it

Bingel [31]

I'm assuming the deck is the shaded area.

To find the area of the deck, find the area of the large circle and subtract the area of the small circle from it:

A of large circle: R = (4.2/2) + 1.7 = 3.8; area: 3.8^2 * pi is about 45.3.

A of small circle: r = 4.2/2 = 2.1; area: 2.1^2 * pi is about 13.8

Now, subtract:

45.3 - 13.8 = 31.5 meters squared

6 0

3 years ago

Given rectangle ABCD, segment AC is a diagonal, segment BE is perpendicular to segment AC at E. Segment AE = 8 inches and segmen

andriy [413]

Check the picture attached.

Let m(BAE)=m(ACD)=α

(BAE and ACD are congruent, since they are alternate interior angles, or Z angles)

Let m(ABE)=β.

So in triangle ABE, the measures of the angles are 90, α and β degrees.

This means that m(BCE)=β, since the 2 other angles of triangle BCE are 90 and α degrees.

thus, we have the similarity of triangles ABE and BCE,

so the following rations are equal:

$\frac{AB}{BC} = \frac{BE}{CE} = \frac{AE}{BE}$

so

$\frac{AB}{BC} = \frac{x}{5} = \frac{8}{x}$

so

$\frac{x}{5} = \frac{8}{x}$

$x^{2} =40$

$x= \sqrt{40}= \sqrt{4*10}=2 \sqrt{10}$ (inches)

Remark, we can also apply Euclid's theorem directly.