Answer:
Step-by-step explanation:
(4b^2+3)(4b^2-3)
since it is the expanded form of formula a^2-b^2=(a+b)(a-b) we can write,
=(4b^2)^2-(3)^3
=16b^4-9
Answer:
x=47, y=68
Step-by-step explanation:
Add the two equations. Then we get
-y=-68
y=68
Substituting the value of y in the first equation,
8x-6(68)=-32
8x-408=-32
8x=376
x=47
Answer:
Step-by-step explanation:
In this case, the offspring will have two dominant traits and one recessive trait. If One of the Alleles for a traight is dominant, then the expressed traight will be dominant, assuming there is no mixing of traits. So for any offspring with these traits, they can have one or both domiant alleles for the wing shape and body color traits, but they must have both recessive alleles for the eye trait. Using a punnett square, you can find the number, which happens to be 9/64.
Answer:
$25
Step-by-step explanation:
c=30−(0.25)(20)
c=30+(−5)
c=(30+(−5)
30-5
Combine Like Terms
c=25
Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

so.. that'd be the V(x) for such box, now, where is the maximum point at?

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.
so, the volume will then be at