Step-by-step explanation:
sin∅=-3/4 in 4 quadrant which sine is negative there
using soh cah toa
sin=opp/hyp
where our opp=-3 and our hyp=4
using pythagoras theorem
hyp²=opp²+adj²
(4)²=(-3)²+adj²
16=9+adj²
16-9=adj²
adj²=7
adj=√7
from soh cah toa
cos∅=adj/hyp
cos∅=√7/4
What do we know about those two lines?
They are perpendicular, meaning they have the same slope.
We know the slope of both is not zero (neither is vertical).
Therefore either
1) Both slopes are positive and therefore the product is positive
2) Both slopes are negative and therefore the product is positive (minus by a minus is a plus)
For the y intercepts, we know that the line P passes through the origin.
Therefore its Y intercept is zero.
[draw it if this is not obvious and ask where does it cross the y axis]
Therefore the Y intercept of line K and line P is zero.
[anything multiplied by a zero is a zero]
So we know that the product of slopes is positive, and we know that the product of Y intercepts is zero.
So the product of slopes must be greater.
Answer A
Answer:
false: positive and negative numbers are on two completely opposite sides of a number line, coordinate plane, etc. Just like 4 is different than 5, it is the same with positive and negative numbers
Answer:
45 ?
Step-by-step explanation:
Answer:
40x^3 -10x
Step-by-step explanation:
Used math-way to solve this! I'm sorry if wrong, x
