Answer:
1, 2, 3
Step-by-step explanation:
Point slope form is y-y1= m(x-x1)
So u need another x and y ull hav to guess with what u hav so like it could start as 2-1 or 3-0 but it’s ur choice
Answer: B) x + y = 17
1.60x + 2.45y = 34
Step-by-step explanation:
Cost of x = $1.60 per pound
Cost of y = $2.45 per pound
Total pounds of x and y = 17
Cost per pound of mixture = $2
Total number of pounds of the mixture :
x + y = 17
Since the cost per pound of the mixture = 2
Hence ;
(Cost of x * number of pounds of x) + (Cost of y * number of pounds of y)
(1.60 * x) + (2.45 * y) = (cost per pound of mixture * total number of pounds of the mixture)
1.60x + 2.45y = 2 * 17
1.60x + 2.45y = 34
Considering the given graph, the number of solutions for the system of equations is given by:
b.) one
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In a graph, the number of solutions is given by the number of times the lines intersect. Hence, in this problem, the system has one solution, and option b is correct.
More can be learned about a system of equations at brainly.com/question/24342899
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This is pretty simple. All you have to do is make the first and second fraction share a denominator by multiplying them by each other.
6 <span>• 9 = 54
Then multiply each numerator by the opposing denominator.
1 </span><span>• 9 = 9
2 </span><span>• 6 = 12
Here are the new fractions:
9/54
12/54
Now add the 9 and 12 together.
9 + 12 = 21
The complete fraction:
21/54
Subtract 21 from 54 so you can get the remainder of the sweater.
54 - 21 = 33
This is the remainder fraction:
33/54
Can you simplify this? Yes, of course! They can both be divided by 3!
11/18
That is the remainder of the sweater. But you still have to divide it in half! After all, Linda only knitted half of the remaining sweater. Dividing it in half can be done just by multiplying the denominator by 2.
11/36
That should be your answer! Apologies if I got something wrong.</span>
