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Alenkasestr [34]
3 years ago
12

Find the mean, median, mode for 41,41,41,42,42,43,43,43,43,45,45,45,46,46,46,46,46,46,46,49,49,50,51,51,53,54,55,55,56,56,57

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

Mean : 47.48

Median : 46

Mode : 46

Step-by-step explanation:

1) Mean= Total sum /  Total Entries

Sum = 41*3 +42*2+43*4+45*3+46*7+49*2+50*1+51*2+53*1+54*1+55*2+56*2+57*1

Sum = 123+84+172+135+322+98+50+102+53+54+110+112+57

sum = 1472

Total Entries = 3+2+4+3+7+2+1+2+1+1+2+2+1= 31

Mean = 1472/31

         = 47.48

ii) Median = 16th Value

As there are total 31 entries , Hence the Median will be the entry coming on 16th place

Median = 46

iii) Mode

The entry which is repeated for the maximum number of times is called the mode. Here 46 is repeated the most. hence 46 is the mode

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The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

x(t) = (1-t)0 + t×2 = 2t  

y(t) = (1-t)0 + t×3 = 3t

z(t) = (1-t)0 + t×4 = 4t

Finding its derivative;

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The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

After solving the integration over the limit 0 to 1, we will get;

\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

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Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

Learn more about integration here:

brainly.com/question/18125359

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