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3 years ago

Please help!

2 answers:

8 0

<span>The area to be determined is a segment of the circle.

Since central angle is 120 degrees and 120/360 = 1/3
area of sector of circle is (1/3)*36pi = 12pi
For the area of triangle, you can split it into 2 30-60-90 right triangles with sides 3:3sqrt3:6
thus base of triangle is 6sqrt3 and height is 3

Area = 1/2 * 3* 6sqrt3 = 9sqrt3 -->
segment area = 12pi - 9sqrt3</span>

KiRa [710]3 years ago

3 0

The area to be determined is a segment of the circle.

Since central angle is 120 degrees and 120/360 = 1/3

area of sector of circle is (1/3)*36pi = 12pi

For the area of triangle, you can split it into 2 30-60-90 right triangles with sides 3:3sqrt3:6

thus base of triangle is 6sqrt3 and height is 3

Area = 1/2 * 3* 6sqrt3 = 9sqrt3 -->

segment area = 12pi - 9sqrt3

I just did this so I know it's correct.

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Step-by-step explanation:

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3 years ago

Please answer fast this is a test question

pishuonlain [190]

Answer:

Step-by-step explanation:

We can actually make the two equal each other like so:

3d-4=12d/6

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18d=12d+24

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3 years ago

** GIVING BRAINLIEST*** HELP PLEASE!

goldenfox [79]

Answer:

C 3(n/5)

Step-by-step explanation:

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3 years ago

An amusement park has 11 roller coasters. In how many ways can you choose 4 of the roller coasters to ride during your visit to

Vadim26 [7]

4!=4*3*2*1=24
11!=11*10*9*8*7*6*5*4*3*2*1=39916800
7!=7*6*5*4*3*2*1=5040
n choose k
how many ways are there to choose k rollercoasters from n choices?

$\left(\begin{array}{ccc}n\\k\end{array}\right)$ = $\frac{n!}{k!(n-k)!}$

$\left(\begin{array}{ccc}11\\4\end{array}\right)$ = $\frac{11!}{4!(11-4)!}$ = $\frac{39916800}{24(7)!}$ = $\frac{39916800}{24(5040)}$ = $\frac{39916800}{120960}$ =330

330 ways

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4 years ago