Question

Use the graph to complete the statements.

Answer 1

The slope of JK is -6/5.

The slope of PQ is 12/ 15.

These lines are neither parallel nor perpendicular.

Step-by-step explanation:

From the graph shown,

It can be determined that the point J is (0,5) and K is (10,-7).

The point P is (-5,-8) and Q is (10,4).

The formula for slope is given by,

Slope = $\frac{y2-y1}{x2-x1}$

To find the slope of line JK :

J ⇒ (0,5) = (x1,y1)

K ⇒ (10,-7) = (x2,y2)

Slope of JK = $\frac{-7-5}{10-0}$

⇒ $\frac{-12}{10}$

⇒ $\frac{-6}{5}$

∴ The slope of JK is -6/5.

To find the slope of line PQ :

P ⇒ (-5,-8) = (x1,y1)

Q ⇒ (10,4) = (x2,y2)

Slope of PQ = $\frac{4+8}{10+5}$

⇒ $\frac{12}{15}$

∴ The slope of PQ is 12/ 15.

To find the relation between two lines :

• The parallel lines have same slope.
• The perpendicular lines have a slope of negative reciprocal.

∴ These lines are neither parallel nor perpendicular.

Answer 2

Answer:

The slope of JK is -6/5

The slope of PQ is 4/5

The lines are Neither parallel nor perpendicular