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Romashka-Z-Leto [24]
3 years ago
12

The following picture shows two gears meshed together with the arrows lined up. Gear A has 48 teeth, while gear B has 28 teeth.

Suppose the gears begin turning. How many complete revolutions would gear B need to make before the arrows are lined up again?
Mathematics
1 answer:
spin [16.1K]3 years ago
3 0

Answer:  12

<u>Step-by-step explanation:</u>

The LCM of 48 and 28 is 336

It would take 336 ÷ 28 = 12 revolutions of gear B

and 336 ÷ 48 = 7 revolutions of gear A

to match up the arrows.

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The sum of the areas of two circles is 8pie square meters. Find the length of a radius of each circle ifone of them is twice as
NeX [460]
Nice

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the areas are
pir^2+pi(2r)^2
they add to 8pi

8pi=pir^2+pi(2r)^2
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8pi=pi(r^2+(2r)^2)
divide both sides by pi
8=r^2+(2r)^2
expand
8=r^2+4r^2
add
8=5r^2
divide by 5
8/5=r^2
sqrt both sides
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5 0
3 years ago
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5 0
3 years ago
Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form
Anestetic [448]

Answer:

Final answer is x-6y=23

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

\frac{1}{6}x+\frac{5}{6}=y

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

y-y_1=m\left(x-x_1\right)

y-(-3)=\frac{1}{6}\left(x-5\right)

y+3=\frac{1}{6}x-\frac{5}{6}

y=\frac{1}{6}x-\frac{5}{6}-3

y=\frac{1}{6}x-\frac{23}{6}

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is x-6y=23

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3 years ago
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These are the steps. Just follow the numbers on the left hand side. Hopes this helps. The answer is -3.

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