Answer: $7,740
Explanation:
Given, At December 31, Accounts receivable = $238,000
Allowance for uncollectible accounts = 3% of (accounts receivable)
∴ Allowance for uncollectible accounts = 3% of ($238,000 )
=$(0.03 ×238,000) [3% = 0.03]
= $ (7140)
= $7,140
Allowance for uncollectible accounts (credit) before any adjustments= $600
The amount of the adjustment for uncollectible accounts = Allowance for uncollectible accounts + $600
= $7,140 + $600
= $7,740
Hence, The amount of the adjustment for uncollectible accounts would be: <u>$7,740.</u>
Answer:
The answer is: 14,400 different production sequences are possible
Explanation:
For this calculation I will assume that the first 5 operations can be made in any order, as well as the last 5.
For the first set of machining operations, since they can go in any order, you choose one operation and then you have 4 operations left, then you choose another operation and you have 3 operations left, then you choose another operation and you have 2 operations left, you choose another option and you have only 1 operation left. This process can be expressed by the following equation: 5 x 4 x 3 x 2 x 1 = 120 possible different combinations. Mathematically it can also be expressed as 5! = 120
The same for the last 5 assembly operations, you have 5 x 4 x 3 x 2 x 1 = 120 possible different combinations.
So to get the total possible combinations of all the process, we just multiply 120 x 120 = 14,000 or 5! x 5! = 14,400
Answer
The answer and procedures of the exercise are attached in a microsoft excel document.
Explanation
Please consider the data provided by the exercise. If you have any question please write me back. All the exercises are solved in a single sheet with the formulas indications.
Answer:
The Amount of pension expense is $195,000
Explanation:
The computation of the amount of pension expenses reported is shown below:
Service cost $150,000
Interest on projected benefit obligation 63,000
Amortization of prior service $54,000
Less: Expected return on plan assets -$72,000
The Amount of pension expense is $195,000
We simply applied the above formula so that the correct value could come
And, the same is to be considered
<u>Answer:</u>Probability of defect=0.617
<u>Explanation:</u>
Given
Mean ∑= 6
Standard deviation σ = 0.20
The standardized scores can be assumed as value <em>x </em>which has to reduced by mean value and divided by standard deviation.
<em>z= (x - </em>∑)/ σ
=(5.9-6)/0.20
=-0.5
<em>z= (x - </em>∑)/ σ
=(6.1-6)/0.20
=0.5
Calculation of probability of defect
<em>P(x≤5.9 or x ≥6.1)</em>
=<em>P(x≤-0.5 or x ≥0.5)</em>
<em>=2p(x≤-0.5)</em>
=2(0.3085)
Probability of defect=0.617
To find the number of units of defect the manfucturing units have to be multiplied with the probability value.
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