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djverab [1.8K]
3 years ago
6

Select a classification for File2 so that: Alice can read and write to File2 Bob and Charlie can write to File2, but can't read

it. Eve can write to File1 but can't read it. Alice has Top Secret, {A,B,C}. Bob has Secret{A,B}, Charlie has Confidential,{C} and Eve is Unclassified. File2 should be classified as
Computers and Technology
1 answer:
natita [175]3 years ago
6 0

Answer:

Top Secret, (A,B,C)

Explanation:

Solution:

Some information are known to be sensitive, and has a higher level of classification.

Examples for such levels are: Secret, Top secret ,Unclassified and  Confidential, and Unclassified.  all users of the system has a  level of clearance. fro a user to be able to gain access to document, he or she must have posses a level of the document.

Now, this is governed by two rules which is stated below:

No user can have access to any information that is considered higher than their level of clearance.

Secondly, a user can write to files only that contains an equal level or lower of his clearance level, this is to stop what is called the write down effect.

It is important to note that ABC, categories determine what type of access is permitted.

Now, for the given example, since, Bob and charlie cannot read it, which shows that the file must be of top priority or importance, then Bob and Charlie needs clearance to the file,the file 2 is considered a top priority.

Therefore, the File 2 is classified as a Top Secret, (A,B,C)

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Answer:

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Explanation:

In the given code firstly we create the object of the integer class that is first in this we pass the integer value that is 7. Then we declare another second integer variable is this variable we pass object as a reference. Then we use the two conditional statements. In the first, if block we check that the object of the class is equal to the reference variable. If it is true it prints Sneezy. otherwise, it will print Grumpy. In second if block we check that the object of the class is equal to the reference variable. but in this time we the equals() function it is the same as(==). If the condition is true it prints Sleepy. otherwise, it will print Doc. So the output of the code is Sneezy Sleepy.

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What type of information is appropriate for headers and footers? Check all that apply.
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Answer:

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When should you create an outline?
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Google is an example of a(n):
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If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support
Molodets [167]

Answer:

Here is the JAVA program. I  have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

   Scanner input = new Scanner(System.in); // create object of Scanner

       String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

           String LOL = "laughing out loud";

           String IDK = "i don't know";

           String BFF = "best friends forever";

           String IMHO = "in my humble opinion";

           String TMI = "too much information";

           String TYT = "take your time";

           String IDC = "I don't care";

           String FYI = "for your information";

           String BTW = "by the way";

           String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

           System.out.println("Input an abbreviation:" + " ");

           if(input.hasNext()) { // reads the abbreviation form the user

           abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

    switch(abbreviation) {

       case "LOL" : System.out.println(LOL);

                    break;

       case "IDK" : System.out.println(IDK);

                    break;

       case "BFF" : System.out.println(BFF);

                    break;

       case "IMHO": System.out.println(IMHO);

                     break;

       case "TMI": System.out.println(TMI);

                     break;

       case "TYT": System.out.println(TYT);

                     break;

       case "IDC": System.out.println(IDC);

                     break;

       case "FYI": System.out.println(FYI);

                     break;

       case "BTW": System.out.println(BTW);

                     break;

       case "OMG": System.out.println(OMG);

                     break;

                     

       default    : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

5 0
3 years ago
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