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djverab [1.8K]
3 years ago
6

Select a classification for File2 so that: Alice can read and write to File2 Bob and Charlie can write to File2, but can't read

it. Eve can write to File1 but can't read it. Alice has Top Secret, {A,B,C}. Bob has Secret{A,B}, Charlie has Confidential,{C} and Eve is Unclassified. File2 should be classified as
Computers and Technology
1 answer:
natita [175]3 years ago
6 0

Answer:

Top Secret, (A,B,C)

Explanation:

Solution:

Some information are known to be sensitive, and has a higher level of classification.

Examples for such levels are: Secret, Top secret ,Unclassified and  Confidential, and Unclassified.  all users of the system has a  level of clearance. fro a user to be able to gain access to document, he or she must have posses a level of the document.

Now, this is governed by two rules which is stated below:

No user can have access to any information that is considered higher than their level of clearance.

Secondly, a user can write to files only that contains an equal level or lower of his clearance level, this is to stop what is called the write down effect.

It is important to note that ABC, categories determine what type of access is permitted.

Now, for the given example, since, Bob and charlie cannot read it, which shows that the file must be of top priority or importance, then Bob and Charlie needs clearance to the file,the file 2 is considered a top priority.

Therefore, the File 2 is classified as a Top Secret, (A,B,C)

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A cycle merchant allows 15% discount on the marked price of a bicycle and still he makes a profit
lions [1.4K]

Answer:

The program in Java is as follows:

public class Main{

public static void main(String[] args) {

 double discount_percent = 0.15;

 double discount_amount = 600;

 double profit = 0.20;

 double marked_price = discount_amount/discount_percent;

 double cost_price = marked_price/(1 + profit);

 System.out.println("Marked Price: "+marked_price);

 System.out.println("Cost Price: "+cost_price);

}}

Explanation:

For explanation purpose, let

MP \to Marked Price

\%D \to Percentage discount

D \to Discounted amount

\%P \to Percentage Profit

C \to Cost Price

The marked price (i.e. selling price) is calculated discount using:

MP = \frac{D}{\%D}

The derived formula of the cost price from percentage profit and Marked Price is:

C = \frac{M}{1 + \%P * 100}

So, the explanation is as follows:

The next three lines declare and initialize the given parameters

<em>  double discount_percent = 0.15;</em>

<em>  double discount_amount = 600;</em>

<em>  double profit = 0.20;</em>

Calculate marked price

 double marked_price = discount_amount/discount_percent;

Calculate cost price

 double cost_price = marked_price/(1 + profit);

Print marked price

 System.out.println("Marked Price: "+marked_price);

Print Cost price

 System.out.println("Cost Price: "+cost_price);

3 0
3 years ago
toThePowerOf is a method that accepts two int arguments and returns the value of the first parameter raised to the power of the
inessss [21]

Answer:

cubeVolume = toThePowerOf(cubeSide, 3)

Explanation:

The function toThePowerOf, receives two int arguments say, a and b, where a is the first argument and b is the second argument as follows:

toThePowerOf(a,b)

The function returns the first argument(a) raised to the power of the second argument (b) i.e a ^ b as follows:

toThePowerOf(a, b){

return a^b

}

In the call to the function, the first argument a, is replaced with the variable cubeSide and the second argument b is replaced with the value 3.

Hence, the returned result becomes cubeSide ^ 3 which is then stored in a variable cubeVolume as follows:

cubeVolume = toThePowerOf(cubeSide, 3)

6 0
3 years ago
Give state diagrams of DFAs that recognize the following languages.
k0ka [10]

Answer:

Following is attached the solution of each part step-by-step. I hope it will help you!

Explanation:

6 0
3 years ago
According to Amdahl's Law, what is the speedup gain for an application that is 60% parallel and we run it on a machine with 4 pr
rodikova [14]

With four processing cores, we get a speedup of 1.82 times.

<h3>What is Amdahl's Law?</h3>

Amdahl's law exists as a formula that provides the theoretical speedup in latency of the implementation of a task at a fixed workload that can be expected of a system whose resources exist improved.

Amdahl's law exists that, in a program with parallel processing, a relatively few instructions that hold to be completed in sequence will have a limiting factor on program speedup such that adding more processors may not complete the program run faster.

Amdahl's law stands also known as Amdahl's argument. It is utilized to find the maximum expected progress to an overall system when only part of the system exists improved. It is often utilized in parallel computing to indicate the theoretical maximum speed up utilizing multiple processors.

Hence,  With four processing cores, we get a speedup of 1.82 times.

To learn more about Amdahl's Law refer to:

brainly.com/question/16857455

#SPJ4

6 0
2 years ago
Which attributes does not come in tag?
Ne4ueva [31]

Answer:

length is your answer

Explanation:

Have a great day! ^-^

can you me as brainliest if its right? i need 10000 points and 35 brainliest's to rank up to genius

4 0
3 years ago
Read 2 more answers
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