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Debora [2.8K]
3 years ago
5

Consists of a variety of circuitry and components that are packaged together and connected directly to the motherboard. it perfo

rms all the mathematical and logical operations. it is considered to be the brains of the computer where all the calculations occur.
Computers and Technology
1 answer:
Goshia [24]3 years ago
3 0
This is true because the motherboard is the main holder of all the operation and connection of all the system.
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Give three examples of NON-TRADITIONAL web authoring tools<br> 3 pour
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4 0
2 years ago
Write an expression that prints 'You must be rich!' if the variables young and famous are both True.
Rufina [12.5K]

Answer:

Following are the expression to this question:

if (young and famous==True):

Explanation:

For print, the given expression the code requires some modification that can be defined as follows:

young = True#defining a bool variable that holds a value True

famous = True#defining a bool variable that holds a value True

if (young and famous==True):#defining if block that check variable value

   print('You must be rich!')#print message

else:#else block  

   print('There is always the lottery...')#print message

Output:

You must be rich!

Code explanation:

In the above-given code, two variable "young and famous" is declared, that hold a "True" which is a bool value, in this code, a conditional statement has used, that checks variable value, which can be defined as follows:

  • In the if block, it uses the above declared variable with and gate to check its value is equal to true.
  • If the condition is true, it will print the true block message, otherwise, go to the else block in this, it will print the else block message.
4 0
2 years ago
To prevent class objects from being copied or assigned, you can:
Travka [436]

Answer:

The correct answer to the following question is option 4.

Explanation:

The private class does not mean that the package-private, it means that no other class can see its members.  

It is used in creating the building blocks which is implementing the internal functionality that you don't want to visible to the other projects using the library.

We can use private constructor to ensure that more than one object cannot be created at the time.

6 0
3 years ago
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
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