What is the GCF of 147y^3 , 245y^2
1 answer:
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Answer:
Mr. devito needs to buy 40 packs
Step-by-step explanation:
Given:
Total number of fourth grade students = 118
The number of pencils in one pack = 6
The number pencil each student gets =2
To find:
The number of packs of pencils that is to be bought = ?
Solution:
To give all the 118 fourth grade students each 2 pencils , the total number of pencils needed will be
= >
=> 236 Pencils
We know that a pack contains 6 pencils, so the number of pack that has to be bought , in order to have 236 pencils will be
=>
On substituting the values
=>
=> 39.33
=> 40
1. The area of the photograph is:
A=LxW
A is the area of the photograph (A=54 in²).
L is the lenght of the photograph (L=12-4x).
W is the widht of the photograph (W=12-2x)
2. When you substitute these values into the formula A=LxW, you obtain:
A=LxW
54=(12-4x)(12-2x)
3. When you apply the distributive property, you have:
54=144-24x-48x+8x²
8x²-72x+144-54=0
4. Finally, you obtain a quadratic equation for the area of the photo:
8x²-72x+90=0
5. Therefore, the answer is:
8x²-72x+90=0
A=LxW
A is the area of the photograph (A=54 in²).
L is the lenght of the photograph (L=12-4x).
W is the widht of the photograph (W=12-2x)
2. When you substitute these values into the formula A=LxW, you obtain:
A=LxW
54=(12-4x)(12-2x)
3. When you apply the distributive property, you have:
54=144-24x-48x+8x²
8x²-72x+144-54=0
4. Finally, you obtain a quadratic equation for the area of the photo:
8x²-72x+90=0
5. Therefore, the answer is:
8x²-72x+90=0