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Sonja [21]
3 years ago
8

S = 2πrh + 2πr², for h

Mathematics
1 answer:
diamong [38]3 years ago
6 0

Answer:

Step-by-step explanation:

This is a literal equation, and for some reason, students literally freak out about solving them.  We will isolate h the same way we would if we were solving an equation for x.  In order to get the term with the h in it all by itself, we have to move everything else away from that term.  The 2πr² is added on the left, so we will move it by subtracting it from both sides, giving us

S-2\pi r^2=2\pi rh

Then we need to get the h alone.  Everything on the right side of the equals sign is multiplied together, so the "undoing" of multiplication is division, so that's what we'll do.  Divide everything away from the h:

\frac{S-2\pi r^2}{2\pi r}=h

which is choice C.

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yuson must complete 30 hours of community service. she does 2 hours each day. which linear equation represents the hours yuson h
algol [13]

Answer:

30-2x

Step-by-step explanation:

yuson has to finish am total of 30 hours in community service

she does 2 hours each day

in x days, hour of service done=2x

after x days hours of service left=30-2x

therefore the linear equation representing the hours yuson has left after x days is:

30-2x

6 0
3 years ago
Find the solution to the following system using substitution. y = - 4 + 9 y = 3x - 5
lbvjy [14]

Answer:

1/2, 11/6

Step-by-step explanation:

y=-4+9y

9y-y=4

8y=4

y=1/2

3x-5=1/2

3x=5+1/2=11/2

x=11/6

6 0
2 years ago
Area of this rectangular pyramid please
dalvyx [7]
The rectangular prism has an area of 1188.
4 0
3 years ago
A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,
algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}

Where v_i is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is [0, \pi/2]. The critical  points of the function are those who make d'(\theta)=0:

d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}

d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...

The critical value inside the interval is \pi/4.

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft

The second step is to find the values of the function at the endpoints of the interval:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft

The biggest value of f is gived by \pi/4, therefore \pi/4 is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

4 0
3 years ago
- 7x + 12 - 2x = 23+13x
SpyIntel [72]
Hello, the answer is x=-1/2
Here are the steps....
<span><span><span><span><span>−<span>7x</span></span>+12</span>+</span>−<span>2x</span></span>=<span>23+<span>13x</span></span></span><span><span><span>(<span><span>−<span>7x</span></span>+<span>−<span>2x</span></span></span>)</span>+<span>(12)</span></span>=<span><span>13x</span>+23</span></span>(Combine Like Terms)<span><span><span>−<span>9x</span></span>+12</span>=<span><span>13x</span>+23</span></span><span><span><span>−<span>9x</span></span>+12</span>=<span><span>13x</span>+<span>23
</span></span></span><span><span><span><span>−<span>9x</span></span>+12</span>−<span>13x</span></span>=<span><span><span>13x</span>+23</span>−<span>13x</span></span></span><span><span><span>−<span>22x</span></span>+12</span>=<span>23
</span></span><span><span><span><span>−<span>22x</span></span>+12</span>−12</span>=<span>23−12</span></span><span><span>−<span>22x</span></span>=<span>11
</span></span><span><span>−<span>22x</span></span><span>−22</span></span>‌=<span><span>‌<span>11<span>−22</span></span></span>‌</span><span>x=<span>‌<span><span>−1</span>2</span></span></span><span>
</span>Hope this helps you!!
6 0
3 years ago
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