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3 years ago

Hey there guys could anyone help me out here? tutors are unavailable and help would really be appreciated.

Mathematics

2 answers:

Anna11 [10]3 years ago

6 0

It would be 50 because most shapes equal 360 and 130x2= 260 and 300-260= 100 then dived 100 by 2 and you get 50

Scilla [17]3 years ago

5 0

Answer:

50 degrees

Step-by-step explanation:

because it is a parallelogram, angle B = angle D, and angle C = angle A

that means we have 130(2) = 260 degrees that we know.

the total interior angles of a parallelogram = 360

360 - 260 = 100 degrees left. BUT because those are the total amount of angles left, those are angles A and C combined, so you have to divide 100 in half to get the angle A/ angle DAB

100/2 = 50 degrees. hope this helps! leave a question if you are still confused.

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Sedbober [7]

Basically, you are looking for the ARC SINE of .994 which is
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8 0

2 years ago

Question

balandron [24]

Answer:

The approximate percentage of SAT scores that are less than 865 is 16%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 1060, standard deviation of 195.

Empirical Rule to estimate the approximate percentage of SAT scores that are less than 865.

865 = 1060 - 195

So 865 is one standard deviation below the mean.

Approximately 68% of the measures are within 1 standard deviation of the mean, so approximately 100 - 68 = 32% are more than 1 standard deviation from the mean. The normal distribution is symmetric, which means that approximately 32/2 = 16% are more than 1 standard deviation below the mean and approximately 16% are more than 1 standard deviation above the mean. So

The approximate percentage of SAT scores that are less than 865 is 16%.

8 0

2 years ago

During the first year Sherry worked as a lifeguard, she was paid at a rate of $12.75 per hour.

lara [203]

Answer:

Step-by-step explanation:

5 0

3 years ago

A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre

Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

Two groups of 22 patients, hence, the standard errors are:

$s_1 = \frac{45.1}{\sqrt{22}} = 9.6154$

$s_2 = \frac{26.4}{\sqrt{22}} = 5.6285$

The distribution of the differences is has:

$\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{25 - 0}{11.14}$

$t = 2.2438$

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0

2 years ago

Which is the answer? :(

klio [65]

Answer:

the answer is :)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers