The ship movement is an illustration of distance and bearing
The ship is 31.97 miles from its point of departure
<h3>The distance from the point of departure?</h3>
The given parameters are:
- Distance east = 40 milies
- Distance southwards = 70 miles
- Angle = 12 degrees
See attachment for the image of the above parameters
The distance (x) from the point of departure is then calculated using the following cosine function
a^2 = b^2 + c^2 - 2bc * cos(Ф)
So, we have:
x^2 = 40^2 + 70^2 - 2 * 40 * 70 * cos(12)
Evaluate the exponent and the product
x^2 = 6500 - 5477.63
Evaluate the difference
x^2 = 1022.37
Evaluate the exponent
x = 31.97
Hence, the ship is 31.97 miles from its point of departure
Read more about distance and bearing at:
brainly.com/question/24142612
The correct answer is <u><em>No!!</em></u>
Hope This Helps!!!
Answer:
6 7/8 minutes
Step-by-step explanation:
Say the entertainment segments are each x minutes long. Then, we have the equation:
x + x + 1 1/4 = 15
2x + 1 1/4 = 15
2x = 15 - 1 1/4
We need a common denominator. 1 1/4 = 5/4 and 15 = 60/4, so we now have:
60/4 - 5/4 = 55/4. Then: 2x = 55/4
Divide by 2 from both sides:
(55/4) / 2 = 55/8 = 6 7/8
Thus, each entertainment segment is 6 7/8 minutes long.
Hope this helps!
Quart because it's bigger than a pint and a quart is the closest to a gallon
4^1= 4. the exponential form is b^e=n, while log is logb n=1.