(| 5 - 3x | - 1) - (1 - 3x) = 0
|5 - 3x| - 1 - 1 + 3x = 0
|5 - 3x| - 2 + 3x = 0
1) (5 - 3x) - 2 + 3x = 0, if 5 - 3x >= 0
3 = 0. has no solutions
2) -(5 - 3x) - 2 + 3x = 0, if 5 - 3x < 0
-5 + 3x - 2 + 3x = 0
6x = 7
x = 7/6
5 - 3x < 0
-3x < -5
x > 5/3.
has no solutions
Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
Answer:
56
Step-by-step explanation:
Answer:
false
Step-by-step explanation:
3x + 4y = - 8
The equation of a line in standard form is Ax + By = C
where A is a positive integer and B, C are integers
Express the line in ' slope- intercept form '
y = mx + c → (m is the slope and c is the y-intercept)
here m = - 
and c = - 2
hence y = - x - 2 → equation in slope- intercept form
multiply all terms by 4
4y = - 3x - 8
add 3x to both sides
3x + 4y = - 8 → in standard form
