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2 years ago

HELP ASAP!!! What is the slope of this line? (DO NOT ANSWER WITH A LINK!!!)

Mathematics

2 answers:

algol [13]2 years ago

6 0

Answer:

-2/3

Step-by-step explanation:

the triangle on the line is 2 by 3 and the slope formula is:

rise over run aka length over height!

Since the line is going downhill it would be negative!

Hope this helped!

larisa86 [58]2 years ago

3 0

Answer:

-2/3

Step-by-step explanation:

Start with looking at the y-axis, and count down the line until you get to a definite point. So we can see there is a definite point at (0,4) and (3,2). To get from (0,4) to (3,2), we have to go down 2 (-y) and to the right by 3 (positive x).

Slope formula is y/x, so our slope would be -2/3!

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Read 2 more answers

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$