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slega [8]
3 years ago
13

What values are solutions of 0 =2xexponent of 2 -6x-8

Mathematics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

x = -1 and x = 4

Step-by-step explanation:

Firstly solve the quadratic expression of

2x^2-6x-8 = 0....it gives you the two brackets of.....(2x-8)(x+1)=0

then...you equate the two brackets to 0.separately

2x-8 = 0....which gives you...x = 4...as the first solution..then..;

x+1 = 0....which gives you...x = -1...as the second solution

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Point Q’ is the image of Q (3,-4) under a reflection across the x-axis
7nadin3 [17]

Answer:

Q' (-3,4)

Step-by-step explanation:

A reflection across the x-axis would mean that only the x value of the point would change. This means that the y value would still be 4. To find the x value, just flip it to a negative. The negative of 3 is -3

5 0
3 years ago
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Find the next two terms in this sequence. 1/2, 3/4, 7/8, 15/16
Dominik [7]

Answer 17/18 , 19,20

Step-by-step explanation:

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3 years ago
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Si en 11 cajas de chocolates hay 220 chocolates en total. Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.
pochemuha

Answer:

Habrá 100 chocolates en total en 5 cajas de chocolates.

Step-by-step explanation:

Esta pregunta es resolvida usando proporciones, con lo uso de regla de tres .

11 cajas, 220 chocolates:

Entonces:

\frac{220}{11} = 20

20 chocolates por caja.

Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.

20 chocolates por caja, entonces:

5*20 = 100

Habrá 100 chocolates en total en 5 cajas de chocolates.

6 0
2 years ago
How do you solve sin (5pi/3) without a calculator?
Savatey [412]

very simple, we use the formula sin(a+b)=sinacosb + sinbcosa and sin(20)=2sinacosa

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First, we use sin(a+b)=sinacosb + sinbcosa

sin(5pi/3)=sin(2pi/3+3pi/3)= sin(2pi/3+pi)= sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)

but we know that sin(pi)= 0, and cos (pi) = -1, so sin(5pi/3)= - sin(2pi/3)

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sin<span>(5pi/3)=  -2sin(pi/3)cos(pi/3)</span>

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5 0
3 years ago
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Work out the reciprocal of 0.4
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Answer:

1/0.4=10/4=5/2...............

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