What values are solutions of 0 =2xexponent of 2 -6x-8

Mathematics

1 answer:

Svetlanka [38]3 years ago

3 0

Answer:

x = -1 and x = 4

Step-by-step explanation:

Firstly solve the quadratic expression of

2x^2-6x-8 = 0....it gives you the two brackets of.....(2x-8)(x+1)=0

then...you equate the two brackets to 0.separately

2x-8 = 0....which gives you...x = 4...as the first solution..then..;

x+1 = 0....which gives you...x = -1...as the second solution

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