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3 years ago

−6x+14<−28 OR 9x+15≤−12

Mathematics

2 answers:

Serhud [2]3 years ago

6 0

Answer:x>7 or x ≤ -3

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

Step-by-step explanation:

nadezda [96]3 years ago

3 0

Answer:

x> 7 OR x ≤−3

Step-by-step explanation:

−6x+14<−28 OR 9x+15≤−12

Solve them separately and then put back together

−6x+14<−28

Subtract 14 from each side

-6x +14-14 <-28-14

-6x <-42

Divide each side by -6, remembering to flip the inequality

-6x/-6 > -42/-6

x> 7

9x+15≤−12

Subtract 15 from each side

9x +15-15 ≤−12 -15

9x ≤−27

Divide each side by 9

9x/9 ≤−27/9

x ≤−3

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Write a polynomial function, p(x) with degree 3 that has p(7)=0

MArishka [77]

Answer:

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

$(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}$

Take a = x

b = 7

Substitute in the identity we get

$(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343$

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

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