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3 years ago

−6x+14<−28 OR 9x+15≤−12

Mathematics

2 answers:

Serhud [2]3 years ago

6 0

Answer:x>7 or x ≤ -3

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

Step-by-step explanation:

nadezda [96]3 years ago

3 0

Answer:

x> 7 OR x ≤−3

Step-by-step explanation:

−6x+14<−28 OR 9x+15≤−12

Solve them separately and then put back together

−6x+14<−28

Subtract 14 from each side

-6x +14-14 <-28-14

-6x <-42

Divide each side by -6, remembering to flip the inequality

-6x/-6 > -42/-6

x> 7

9x+15≤−12

Subtract 15 from each side

9x +15-15 ≤−12 -15

9x ≤−27

Divide each side by 9

9x/9 ≤−27/9

x ≤−3

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