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alexandr402 [8]
3 years ago
6

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

3 × 10^8 meter/second).
Computers and Technology
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

v = \frac{(xf-xo)}{(t-to)}

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

t =\frac{xf}{v}  =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.

⇒ t = 8.7*10⁻⁴ sec.

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Answer:

The program to this question can be given as:

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Explanation:

The description of the above python program can be given as:

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Explanation:

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Elodia [21]

Answer:

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3 years ago
Recall that within the ArrayBoundedQueue the front variable and the rear variable hold the indices of the elements array where t
Citrus2011 [14]

Answer:

int n = elements.length;

if(rear < n) {

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Explanation:

Options are not made available; However, I'll answer the question base on the following assumptions.

Assumptions

Array name = elements

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Read more: brainly.com/question/14810228

8 0
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