We know that
a(n)=4n+1
To find the sum of the first n<span> terms of an arithmetic series
use the formula
</span><span><span>Sn</span>=<span>n(<span>a1</span> + <span>an</span>)/2
</span></span>a1--------------> is the first term
an--------------> is the last term
n--------------- > <span>is the number of terms
</span>we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890
the answer is 1890
Answer:
Hi there!
The answer for number 13 is 2.
I picked two coordinates: (1,1) and (2,3)
Then I used the (y1-y)/(x1-x) equation to get 2.
The answer for number 14 is 2.
I picked two coordinates: (1,0) and (2,2)
Then I used the (y1-y)/(x1-x) equation to get 2.
Answer:
- 2x + y
- 3 x - 2y
- -1
2(3 x - 2y) = -6x + 4y
2x + y + -6x + 4y + -1 = -4x + 5y -1
Peggy completed more because more equal parts that are smaller with more shaded means it has to be more.
Answer:
Step-by-step explanation:
we know that
The <u>Least Common Multiple</u> (LCM) of a group of numbers is the smallest number that is a multiple of all the numbers.
we have
15,18 and 25
Decompose the numbers in prime factors
Multiply common and uncommon numbers with their greatest exponent
so
The LCM is equal to
