Answer:
(x-2),(x+1)
Step-by-step explanation:
2x + 5y = 2
-3x - y =-3
-3x - y = -3
y = 3x - 3
substitute y = 3x - 3 into the first equation.
2x + 5y = 2
2x + 5(3x - 3) = 2
2x + 15x - 15 = 2
17x - 15 = 2
solve for x in 17x - 15 = 2
17x - 15 = 2
17x = 2 + 15
17x = 17
x = 1
substitute x = 1 into y = 3x - 3
y = 3x - 3
y = 3(1) - 3
y = 3 - 3
y = 0
(1, 0) << the answer
hope this helped, God bless!
First plug in g(x) into f(x)
F((g(x))=2(2x+3)
And now you plug in -8
F(g(-8))=2(-16+3)
F(g(-8))=2(-13)
F(g(-8))=-26
(3x^3 - 5x^2 -4x + 4) / (x-2) = (3x-2)(x+1) when x ≠2
Answer:
one solution
Step-by-step explanation:
2/3(3y+6)=0
Multiply by 3/2
3/2 *2/3(3y+6)=0*3/2
3y+6 = 0
Subtract 6 from each side
3y = -6
Divide by 3
3y/3 = -6/3
y = -2
There is one solution