The 6 is in the thousandth place so you round with that being the last number
since we have a 55 after the 6, we round up
so we get
3,989.237
Answer:
Step-by-step explanation:
for two matrices A, B to be Similar, then A = SBS⁻¹
A=SBS−1⟹trace(A)=trace((SB)(S−1))=trace((S−1)(SB))=trace((SS−1)B)=trace(B)
Answer:

Or

Step-by-step explanation:
We want to find the angle which forms a y-coordinate of 
on the unit circle.
The y-coordinate on the unit circle is given by
.
This implies that 



Or

Answer:
z = 1.960
Step-by-step explanation:
The sample proportion is:
p = 715 / 2684 = 0.2664
The standard error is:
σ = √(pq/n)
σ = √(0.266 × 0.734 / 2684)
σ = 0.0085
For α = 0.05, the confidence level is 95%. The z-statistic at 95% confidence is 1.960.
The margin of error is 1.960 × 0.0085 = 0.0167.
The confidence interval is 0.2664 ± 0.0167 = (0.2497, 0.2831).
The upper limit is 28.3%, so the journal can conclude with 95% confidence that the true percentage is less than 29%.
Explanation:
We assume you want to "solve" for some points that are on the graph.
You can observe that the constant (14) is a multiple of the x-coefficient (-2), so it will be convenient to solve for the x-intercept. Set y=0 and solve for x:
-2x = 14
x = -7 . . . . divide by -2
This tells you that (-7, 0) is a point on the graph.
To find another point on the graph with integer coordinates, you can change y by the opposite of the amount of the x-coefficient, or vice versa. Let's change y by +2 from 0 to 2, then we have ...
-2x +5·2 = 14
-2x = 4 . . . . . . subtract 10
x = -2 . . . . . . . divide by -2
This tells you that (-2, 2) is another point on the graph.
The graph of the equation will be the line through these two points.
_____
You can find points on the line any of several ways. One way is to divide this equation by the constant on the right and rearrange so the coefficients are denominators:
x(-2/14) + y(5/14) = 1
x/(-7) + y/(2.8) = 1
These denominators are the respective intercepts, so you know immediately that points (-7, 0) and (0, 2.8) are on the line.
We did this mentally and realized that the y-intercept is not easy to graph. Hence the procedure above was used to find points with integer coordinates.