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amid [387]
3 years ago
12

A jar contains chocolate candies. There are 12 red, 17 blue, 5 green and 6 orange. What is the probability of picking either a g

reen or blue candy, replacing it and then picking an orange candy? Express the probability as a fraction in simplest form
Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

If you sum everything, you'll get 50 candies. Now you know that 50 candies is 100%.

Now you'll calculate the probability:

12 on 50 : 24.00 %

17 on 50 : 34.00 %

5 on 50 : 10.00 %

6 on 50 : 12.00 %

Hope I was helpful :)

Edit :

12/50         17/50           6/50           5/50

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<span>If two numbers on a graph differ by 1, without scale, the amount of inequality could vary infinitely. If the scale is 2, a difference of 1 is half the scale amount, but if the scale is 1000, the difference may be negligible. It is the scale that shows the degree to which the entries differ.</span>
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4 years ago
Yoko is a software saleswoman. Her monthly salary is $2200 plus an additional $40 for every copy of English is Fun she sells.
trapecia [35]

Answer:

y=40x+2200

Step-by-step explanation:

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8 0
4 years ago
Someone please please help me with this ! I would really appreciate it
STALIN [3.7K]

Answer:

Both volumes are the same

Step-by-step explanation:

Volume of cylinder = \pir^{2} h

r = radius

h = height

Since area of the circle is given on top,

Area of a circle = \pir^{2}

We know the area is 12

12 = \pir^{2} (we need to find r)

r = \sqrt{\frac{12}{\pi} }

r = 1.954

Now we can find the cylinder's volume:

Volume of cylinder = \pi(1.954)^{2} (6)

Volume of cylinder = 72

To find the volume of the cuboid, we use

Volume of cuboid = lwh

l = length

w = width

h = height

Volume of cuboid = 6 x 4 x 3

Volume of cuboid =  72

This proves that both the volumes are the same.

3 0
3 years ago
Exercise 21.2
m_a_m_a [10]

Answer:

1.y=3x+1

2.y=1/3x+2

3.y=-2x+5

4.y=4x

5.y=4x-4

6.y=-2x-5

Step-by-step explanation:

(i)

y=mx+c

10=(m)3+1

10=3m+1

10-1=3m

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4 0
3 years ago
Who packed all the pies? Kane’s bakery makes four flavour pies. The weight of each flavour pie is follows:
svet-max [94.6K]
This is an identical problem answered by myself a few days ago.  The answer is reproduced below for your convenience.

It is a very difficult problem if the box sizes are smaller or if there are more pies to pack.
For this particular problem, we first calculate the total weight of pies:
4 apple pies at 700 g = 2800 g
8 banoffee pies at 725 g =5800 g
3 custaard pies at 600 g = 1800 g
5 rhubarb pies at 675 g = 3375 g
for a total of 13775 g

The minimum number of boxes needed will be 13775/4000=3.44, or at least 4 boxes will be required.

We also note that 4 boxes will hold 16000 g, and we only need to pack 13775g, so there is a lot of margin.

We can proceed to do the mechanical way, fill in order of apple, banoffee, custard, and finally rhubarb pies.Following table shows how we fill, naively:      box content               Remaining to pack
Box A B C R     Weight    A B C R   
0                                      4  8  3 5     (original order)
1     4  1  0 0     3525       0  7  3 5
2     0  5  0 0     3625       0  2  3 5
3     0  2  3 0     3250       0  0  0 5
4     0  0  0 5     3375       0  0  0 0
Total weight     13775 g

So that does the job, 4 boxes (minimum) with none exceeding 4000 g to pack a total of 13775 g of pies.
 
Brainly - brainly.com/sf/question/8898504
5 0
3 years ago
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