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amid [387]
2 years ago
12

A jar contains chocolate candies. There are 12 red, 17 blue, 5 green and 6 orange. What is the probability of picking either a g

reen or blue candy, replacing it and then picking an orange candy? Express the probability as a fraction in simplest form
Mathematics
1 answer:
nataly862011 [7]2 years ago
7 0

Answer:

Step-by-step explanation:

If you sum everything, you'll get 50 candies. Now you know that 50 candies is 100%.

Now you'll calculate the probability:

12 on 50 : 24.00 %

17 on 50 : 34.00 %

5 on 50 : 10.00 %

6 on 50 : 12.00 %

Hope I was helpful :)

Edit :

12/50         17/50           6/50           5/50

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Step-by-step explanation:

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Answer: 212998.58

Step-by-step explanation:

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In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
2 years ago
Given the function f(x)=-5x^2-2x+20 find f(3)
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Answer:

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Step-by-step explanation:

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