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amid [387]
3 years ago
12

A jar contains chocolate candies. There are 12 red, 17 blue, 5 green and 6 orange. What is the probability of picking either a g

reen or blue candy, replacing it and then picking an orange candy? Express the probability as a fraction in simplest form
Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

If you sum everything, you'll get 50 candies. Now you know that 50 candies is 100%.

Now you'll calculate the probability:

12 on 50 : 24.00 %

17 on 50 : 34.00 %

5 on 50 : 10.00 %

6 on 50 : 12.00 %

Hope I was helpful :)

Edit :

12/50         17/50           6/50           5/50

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Evaluate the expression below if x = 3 and y= -4.<br> X - Y - 3+ (-57)
Firdavs [7]

Answer:

-53

Step-by-step explanation:

If x=3 and y=-4

Plug the numbers into the equation

3 - (-4) - 3 + (-57)

Now solve the equation right to left

3 - (-4) = 7

7 - 3 = 4

4 - 57 = -53

So the answer is -53

4 0
3 years ago
Read 2 more answers
Which of the following is the graph of y = cos(2x)?
irinina [24]

Answer:

Select the one which meets the following characteristics.

Step-by-step explanation:

y = cos(2x)

Characteristics:

Mean line at y = 0

Amplitude = 1

Period = 360/2 = 180° or pi radians

i.e one complete cos cycle is 0 to 180, next is 180 to 360 and so on

Range : from -1 to 1

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3 years ago
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F(x)=x^2+8x-10 find f(a)+5
Papessa [141]

Answer:

We conclude that:

f(a) + 5 = a² + 8a - 5

Step-by-step explanation:

Given

The function is given by

f(x) = x²+8x-10

To determine

f(a)+5

In order to determine f(a)+5, first, we need to determine f(a).

Now substitute x = a in the function f(x) = x²+8x-10

f(a) = (a)² + 8(a) - 10

f(a) = a² + 8a - 10

Thus,

f(a) + 5 = (a² + 8a - 10) + 5

f(a) + 5 = a² + 8a - 5

Therefore, we conclude that:

f(a) + 5 = a² + 8a - 5

4 0
3 years ago
What did cicero mean by delivery
svlad2 [7]

cicero meant to transfer something to someone .

8 0
4 years ago
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3
adoni [48]

Answer:

The solution set is (5,6).

Step-by-step explanation:

Given equations are:

-6x + 6y= 6         Eqn 1

-6x + 3y=-12      Eqn 2

Subtracting Eqn 2 from Eqn 1

(-6x+6y)-(-6x+3y)= 6-(-12)

-6x+6y+6x-3y=6+12

3y = 18

Dividing both sides by 3

\frac{3y}{3}=\frac{18}{3}\\y=6

Putting y=6 in Eqn 1

-6x+6(6)=6

-6x+36=6

-6x=6-36

-6x=-30

\frac{-6x}{-6}=\frac{-30}{-6}\\x=5

Hence,

The solution set is (5,6).

8 0
3 years ago
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