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Umnica [9.8K]
3 years ago
8

Find the coefficient of x^6 in the binomial expression of (2x+3)^9

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0
Its 2 bc its in front of the variable
S_A_V [24]3 years ago
6 0
By the Binomial Theorem: 
<span>(a + b)^n = sum(k=0 to n) [C(n, k) * a^(n - k) * b^k].
</span>
By letting a = 2x, b = 3, and n = 9 
<span>(2x + 3)^9 = sum(k=0 to 9) [C(9, k) * (2x)^(9 - k) * 3^k]. 
</span>As you can see, the power of x is 9 - k. Since we want the x^6 term: 
<span>9 - k = 6 ==> k = 3
</span>Thus, letting k = 3 yields the term containing x^6 to be: 
<span>C(9, 6) * (2x)^(9 - 3) * 3^4 = 435456x^6. </span>
<span>. </span>
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The average american eats 147 pounds of french fries in 18 years
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What is the volume of this figure?<br><br> Enter your answer in the box.<br><br> yd³
tia_tia [17]

Answer:

4095

Step-by-step explanation:

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6 0
2 years ago
Determine the domain of the function.
pav-90 [236]
Domain \ of \ \frac{\sqrt{x + 3}}{(x + 8)(x - 2)}=(-3\leq x < 2) \cup (2 < x < \infty)

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4 0
3 years ago
Question: "If y &gt; 3, what is the value of n ?"
iris [78.8K]

Answer:

y-3

Problem:

What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?

Step-by-step explanation:

Dividend=quotient×divisor+remainder

So we have

xy-3=(x-1)×(y)+remainder

xy-3=(xy-y)+remainder *distributive property

Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.

We need to get rid of minus y so we need plus y in the remainder.

We also need minus 3 in the remainder.

So the remainder is y-3.

Let's try it out:

xy-3=(xy-y)+remainder

xy-3=(xy-y)+(y-3)

xy-3=xy-3 is what we wanted so we are done here.

7 0
2 years ago
Question 13
kicyunya [14]

Answer:

The c intercept is 42

The t intercepts are: 6, -1 and 7

Step-by-step explanation:

Given

c(t) = (t - 6)(t +1)(t-7)

Solving (a): The c intercept

Simply set t to 0

c(t) = (t - 6)(t +1)(t-7)

c(0) = (0 - 6)(0 +1)(0-7)

c(0) = (- 6)(1)(-7)

c(0) = 42

Solving (b): The t intercept

Simply set c(t) to 0

c(t) = (t - 6)(t +1)(t-7)

(t - 6)(t +1)(t-7) = 0

Split

t - 6= 0,\ \ t +1= 0,\ \ t-7 = 0

Solve for t

t = 6,\ \ t =-1,\ \ t=7

4 0
3 years ago
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