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Umnica [9.8K]
3 years ago
8

Find the coefficient of x^6 in the binomial expression of (2x+3)^9

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0
Its 2 bc its in front of the variable
S_A_V [24]3 years ago
6 0
By the Binomial Theorem: 
<span>(a + b)^n = sum(k=0 to n) [C(n, k) * a^(n - k) * b^k].
</span>
By letting a = 2x, b = 3, and n = 9 
<span>(2x + 3)^9 = sum(k=0 to 9) [C(9, k) * (2x)^(9 - k) * 3^k]. 
</span>As you can see, the power of x is 9 - k. Since we want the x^6 term: 
<span>9 - k = 6 ==> k = 3
</span>Thus, letting k = 3 yields the term containing x^6 to be: 
<span>C(9, 6) * (2x)^(9 - 3) * 3^4 = 435456x^6. </span>
<span>. </span>
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a  He would take an explanatory tone with readers to reveal the different categories of advertisements

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In a paint mixture the following tints are added,200ml of green tint,350ml of blue and 450ml of red tint.Calculate the percentag
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A carpenter has wood planks that are 4 yards, 8 yards, 7 yards, and 3 yards long. what is the mad of these measurements
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6

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8 0
2 years ago
2. In a random sample of 130 World Campus students, 92 were employed full-time.
liberstina [14]

Answer:


Step-by-step explanation:

Given that sample size is 130 >30.  Also by central limit theorem, we know that mean (here proportion) of all means of different samples would tend to become normal with mean = average of all means(here proportions)

Hence we can assume normality assumptions here.

Proportion sample given = 92/130 = 0.7077

The mean proportion of different samples for large sample size will follow normal with mean = sample proportion and std error = square root of p(1-p)/n

Hence mean proportion p= 0.7077

q = 1-p =0.2923

Std error = 0.0399

For 95% confidence interval we find that z critical for 95% two tailed is 1,.96

Hence margin of error = + or - 1.96(std error)

= 0.0782

Confidence interval = (p-margin of error, p+margin of error)

= (0.7077-0.0782,0.7077+0.0782)

=(0.6295, 0.7859)

We are 95% confident that average of sample proportions of different samples would lie within these values in the interval for large sample sizes.

7 0
3 years ago
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