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3 years ago

What is a irrational number between 12.1 and 12.2

Mathematics

2 answers:

GREYUIT [131]3 years ago

7 0

12.123456234576899122567536492848...

sergij07 [2.7K]3 years ago

7 0

Answer:

The required irrational number between 12.1 and 12.2 is 12.1243536859.....

Step-by-step explanation:

To find : What is a irrational number between 12.1 and 12.2 ?

Solution :

An irrational number is defined as the number written in $\frac{p}{q}$ form or in proper fraction where p and q are integers and q is non-zero.

An irrational numbers are non-terminating and non-repeating.

So, An irrational number between 12.1 and 12.2 is any number which is non-terminating and non-repeating there are so many in between.

Let's take, 12.1243536859......

Therefore, The required irrational number between 12.1 and 12.2 is 12.1243536859......

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The product of 5 and 2 less than triple a number equals the product of 7 and 8 more than twice the number. What is the number?

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Answer:Hi,

Let the number be x

Twice the number is 2x

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Step-by-step explanation:

5 0

2 years ago

(x+16)²=12 plz help me and show work

Readme [11.4K]

Answer:

The answer is $x=-16$ ± $2\sqrt{3}$ in exact form or $x=-12.535898$ , $x=-19.464102$ in decimal form.

Step-by-step explanation:

To solve this problem, start by moving all terms to the left side of the equation and simplify. Simplify the equation by subtracting 12 from both sides of the equation and squaring $x+16$ , which will look like $x^{2} +32x+256-12=0$ . Next, simplify the equation again, which will look like $x^{2} +32x+244=0$ .

Then, use the quadratic formula to find the solutions. The quadratic formula looks like $\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}$ .

For this problem, the quadratic variables are as follows:

$a=1$

$b=32$

$c=244$

The next step is to substitute the values $a=1$ , $b=32$ , and $c=244$ into the quadratic formula and solve. The quadratic formula will look like $\frac{-32(+-)\sqrt{32^2-4(1*244)} }{2*1}$ . To simplify the equation, start by simplifying the numerator, which will look like $x=\frac{-32(+-)4\sqrt{3} }{2*1}$ . Then, multiply 2 by 1 and simplify the equation, which will look like $x=-16(+-)2\sqrt{3}$ . The final answer is $x=-16$ ± $2\sqrt{3}$ in exact form. In decimal form, the final answer is $x=-12.535898$ , $x=-19.464102$ .