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Oksi-84 [34.3K]
3 years ago
13

What is a irrational number between 12.1 and 12.2

Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0
12.123456234576899122567536492848...
sergij07 [2.7K]3 years ago
7 0

Answer:

The required irrational number between 12.1 and 12.2 is 12.1243536859.....

Step-by-step explanation:

To find : What is a irrational number between 12.1 and 12.2 ?

Solution :

An irrational number is defined as the number written in \frac{p}{q} form or in proper fraction where p and q are integers and q is non-zero.

An irrational numbers are non-terminating and non-repeating.

So, An irrational number between 12.1 and 12.2 is any number which is non-terminating and non-repeating there are so many in between.

Let's take, 12.1243536859......

Therefore, The required irrational number between 12.1 and 12.2 is 12.1243536859......

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8/10

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4 years ago
Rectangle with area of 10 and length of 2 1/2. Whats the width?
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Hello!

We have been given enough information to solve this question!
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Now, to find the width, we must flip the problem around and use the opposite of multiplication, which is division.

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3 years ago
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Evaluate each expression<br> 6! =<br> 3! • 2=<br> 31
Airida [17]
<h2><u>N-FACTORIAL!</u></h2>

<h3>\mathbb{  \color{brown} \: PROBLEM  }  \:   \:  \bold{{ \color{brown}{1}}} :</h3>

\mathcal{SOLUTION: }

  • \:   \bold{ \red{6!}= 6×5×4×3×2×1= \boxed{ \bold{ \blue{720}}}}

Therefore, <u>the value of 6! is 720</u>.

━┈─────────────────────┈━

<h3>\mathbb{  \color{brown} \: PROBLEM  }  \:   \:  \bold{{ \color{brown}{2}}} :</h3>

\mathcal{SOLUTION: }

  • \bold{3!  \cdot 2! }\implies  \bold{(3×2×1)  \cdot( 2×1 )}

  • \:   \: \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \implies \: \bold{ 6  \times 2} =  \boxed{ \bold{ \blue{12}}}

Therefore, <u>the value of the given expression is 12.</u>

━┈─────────────────────┈━

<h3><u>EXPLANATION</u><u>:</u></h3>
  • The mathematical symbol n! is read as "n factorial". The exclamation point "!" is read as factorial. And please remember or take note that 0! is equal to 1, and 1! is also equal to 1.

_______________∞_______________

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The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:

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