Answer:
Range is {y | y ≥ –11}
Step-by-step explanation:
This is quadratic equation.
<em>A quadratic equation's range can be found if we find the vertex.</em>
For quadratic equations that have a positive number in front of 
, it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>
The formula for vertex of a parabola is:
Vertex = 
Where,
is the coefficient of 
is the coefficient of 
From our equation given, 
and 
Now, coordinate of vertex is 
coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the value [ 
] into the equation. So we have:
Hence, the range would be all numbers greater than or equal to 
Third answer choice is the right one.
Hello
f(x) = 2sin(x)
f(<span>π/6) = 1
f'(x) 2cos(x)
f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b
m = root(3) and b = </span>1 - π/6(root(x))
Hello! :)
Answer:
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An angle bisector divides an angle in half, therefore:
m∠VUW ≅ m∠WUT
Set the expressions equal to each other:
4x + 6 = 6x - 10
Subtract 4x from both sides:
6 = 2x - 10
Add 10 to both sides:
16 = 2x
Divide 2 from both sides:
x = 8.
Substitute in the value of "x" into the equation for ∠WUT:
6(8) - 10 = 48 - 10 = 38°.
The area of the trapezoid is given by the formula A= (a+b)/ 2 * h
in this question a= 8, b= 10, A= 108 inches², and h is what we have to find, substitute what we have got into the formula and you will have:
108= (8+10) /2 *h
108= 9 *h
h= 108/9
h= 12 inches
