Tan(A) = opposite / adjacent
if we call opposite "a" and adjacent "b"
tan(A) = a/b
then...
tan(B) = b/a
because it's on the other angle so "b" is now opposite angle B and "a" is adjacent.
So really you just need to take the reciprocal of the given values.
6. tan(A) = 1.25
reciprocal is flipping the value and using it to divide by 1.
you can keep as decimal , 1/1.25 = 0.8
or change to fraction
1.25 = 5/4
tan(B) = 4/5 or 0.8
7. tan(B) = 0.5
1/0.5 = 2
tan(A) = 2
8. tan(B) = 1
tan(A) = 1
Answer:
The answer is 3 units.
Step-by-step explanation:
Answer:
from my understanding the answer is 175.80
Step-by-step explanation:
Answer:
32
Step-by-step explanation:
Step 1: Define
f(x) = 3x² - 5x - 4
g(x) = -4x - 12
Step 2: Find f(g(x))
f(g(x)) = 3(-4x - 12)² - 5(-4x - 12) - 4
f(g(x)) = 3(16x² + 96x + 144) + 20x + 60 + 4
f(g(x)) = 48x² + 288x + 432 + 20x + 64
f(g(x)) = 48x² + 308x + 496
Step 3: Find f(g(-4))
f(g(-4)) = 48(-4)² + 308(-4) + 496
f(g(-4)) = 48(16) - 1232 + 496
f(g(-4)) = 768 - 736
f(g(-4)) = 32
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
