Answer:
Mass of Na₂CrO₄ = 5.75 g
Explanation:
First of all we will write the balance chemical equation.
2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃
Now we will calculate the moles of AgNO₃.
Number of moles = mass / molar mass
Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 = 169.87 g/mol
Number of moles = mass / molar mass
Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol
Now we will compare the moles of AgNO₃ and Na₂CrO₄ from balance chemical equation.
AgNO₃ : Na₂CrO₄
2 : 1
0.071 : 1/2× 0.071 = 0.0355
Now we will calculate the mass of Na₂CrO₄.
Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol
Mass of Na₂CrO₄ = number of moles × molar mass
Mass of Na₂CrO₄ = 0.0355 mol × 162 g/mol
Mass of Na₂CrO₄ = 5.75 g
