Answer:
The value of final volume inside the vessel 
= 5.17 ml
Explanation:
Initial pressure 
= 6263 mm Hg = 8.24 atm = 835 K pa
Initial temperature 
= 50.1 ° c = 323.1 K
Initial volume 
= 461.1 ml = 0.0004611 
Final temperature 
= - 95.8 ° c = 177.2 K
Finial pressure 
= 411 atm = 41644.6 K PA
We know that
Put all the values in the above equation
⇒ 835 × 
= 41644.6 × 
⇒ = 5.07 × 
⇒ = 5.17 ml
This is the value of final volume inside the vessel.
Answer:
It is an example of coupling an exogenic reaction to an endogenic reaction.
Explanation:
The endergonic reaction is typically being pushed by coupling it to strongly exergonic reaction. This is in most cases via shared intermediates. Most chemical reactions are endergonic in nature. In other word, the are not spontaneous (i.e ΔG>0). Energy must also be applied externally to initiate the reactions. The reactions can also be coupled to exergonic reactions (with ΔG<0) to initiate them through a process known as share intermediate. Because Gibbs Energy can be summed up (i.e is a state function), the combined ΔG of the coupled reaction will be thermodynamically favorable. The decomposition of calcium carbonate is a typical example.
Answer:
THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.
Explanation:
Mass of the unknown substance = 0.50 g
Freezing point of the solution = 3.9 °C
Freezing point of pure benzene = 5.5 °C
Freezing point dissociation constant Kf = 5.12°C/m
First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.
Change in temperature = 5.5 -3.9 = 1.6 °C
Next is to calculate the number of moles or molarity of the compound that dissolved.
Using the formula:
Δt = i Kf m
Assume i = 1
So,
1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene
x = 1.6 * 0.008 / 5.12
x = 0.0128 / 5.12
x = 0.0025 moles.
Next is to calculate the molar mass using the formula, molarity = mass / molar mass
Molar mass = mass / molarity
Molar mass = 0.50 g /0.0025
Molar mass = 200 g/mol
Hence, the molar mass of the unknown compound is 200 g/mol
Answer:
That information is better presented and analyzed in a table.
This table shows you all the information and the answers:
Substance melting point boiling point room temperature conclusion
°C °C °C (state)
A 0 100 25 liquid
B 50 200 25 solid
C -150 10 25 gas
Explanation:
1) Substance A at 25° is above the melting point and below the boiling point, then it is liquid (just like water)
2) Substance B at 25°C is below the melting point, so it is solid.
3) Substance C at 25°C is above the boiling point, so it is gas.
