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Assoli18 [71]
4 years ago
8

A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward a

cceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 98 m and acquired a velocity of The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to:
29 m/s2

31 m/s2

33 m/s2

30 m/s2

32 m/s2
Physics
1 answer:
DIA [1.3K]4 years ago
6 0

Explanation:

The question is incomplete. Here is the complete question.

<em>A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 98 m and acquired a velocity of  30m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to...</em>

<em></em>

Given

initial velocity of rocket u = 0m/s

final velocity of rocket = 30m/s

Height reached by the rocket = 98m

Required

<em>upward acceleration of the rocket </em>

<em></em>

<em>Using the equation of motion below to get the acceleration a:</em>

<em></em>v^2 = u^2+2as\\30^2 = 0^2 + 2(a)(98)\\900 = 196a\\a = \frac{900}{196}\\a = 4.59m/s^2<em></em>

<em></em>

<em>Hence  upward acceleration of the rocket during the burn phase is closest to 5m/s²</em>

<em />

<em>Note that the velocity used in calculation was assumed.</em>

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