Answer:
The unrealistically large acceleration experienced by the space travelers during their launch is 2.7 x 10⁵ m/s².
How many times stronger than gravity is this force? 2.79 x 10⁴ g.
Explanation:
given information:
s = 220 m
final speed, vf = 10.97 km/s = 10970 m/s
g = 9.8 m/s²
he unrealistically large acceleration experienced by the space travelers during their launch
vf² = v₀²+2as, v₀ = 0
vf² = 2as
a =vf²/2s
= (10970)²/(2x220)
= 2.7 x 10⁵ m/s²
Compare your answer with the free-fall acceleration
a/g = 2.7 x 10⁵/9.8
a/g = 2.79 x 10⁴
a = 2.79 x 10⁴ g
To solve this problem, we will use the equation of motion:
v = u + at
where:
v is the final velocity = 117.72 m/sec
u is the initial velocity = zero (body starts falling from rest)
a is the acceleration of the body which is equivalent to acceleration due to gravity = 9.8 m/sec^2
t is the time that we want to calculate
Substitute with the givens in the above equation to get the time as follows:
v = u + at
117.72 = 0 + 9.8t
117.72 = 9.8t
t = 117.72 / 9.8
t = 12.0122 seconds
The correct choice is
B.
Particles at the bottom of the water carry heat energy to the top of the water.
when pot of water is heater, the bottom of pot gets heated. the particles of water in contact with the bottom of the pot gets heat through conduction. after getting heat, these particles of water near the bottom, move away towards top and their position is taken by cooler particles from top. that way heat travels
Answer:
Explanation:
Length = 1.00 m
If the length is 1.0, the vertical distance pivot to bob is cos 35 = 0.819
At the lowest point, vertical distance is 1.0, so the change is the difference, 0.181 meter
The potential energy of that height is converted to kinetic energy of motion, which determines the speed.
PE = KE
mgh = ½mV²
V = √(2gh) = 1.88 m/s