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3 years ago

YALL HELP ME QUICK IN 10 MINS WITH WORKING OUT

Physics

2 answers:

svetlana [45]3 years ago

8 0

Answer:

bro I'm sorry I'm only in 7th grade

Romashka-Z-Leto [24]3 years ago

4 0

The top is kinda cut off but it says “weight =mg

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The Great Sandini is a 60 kg circus performer who is shot from a cannon (actually a spring gun). You don't find many men of his

Alex17521 [72]

Answer:

22m/s

Explanation:

Mass, m=60 kg

Force constant, k=1300N/m

Restoring force, Fx=6500 N

Average friction force, f=50 N

Length of barrel, l=5m

y=2.5 m

Initial velocity, u=0

$F_x=kx$

Substitute the values

$6500=1300x$

$x=\frac{6500}{1300}=5$ m

Work done due to friction force

$W_f=fscos\theta$

We have $\theta=180^{\circ}$

Substitute the values

$W_f=50\times 5cos180^{\circ}$

$W_f=-250J$

Initial kinetic energy, Ki=0

Initial gravitational energy, $U_{grav,1}=0$ \

Initial elastic potential energy

$U_{el,1}=\frac{1}{2}kx^2=\frac{1}{2}(1300)(5^2)$

$U_{el,1}=16250J$

Final elastic energy, $U_{el,2}=0$

Final kinetic energy, $K_f=\frac{1}{2}(60)v^2=30v^2$

Final gravitational energy, $U_{grav,2}=mgh=60\times 9.8\times 2.5$

Final gravitational energy, $U_{grav,2}=1470J$

Using work-energy theorem

$K_i+U_{grav,1}+U_{el,1}+W_f=K_f+U_{grav,2}+U_{el,2}$

Substitute the values

$0+0+16250-250=30v^2+1470+0$

$16000-1470=30v^2$

$14530=30v^2$

$v^2=\frac{14530}{30}$

$v=\sqrt{\frac{14530}{30}}$

$v=22m/s$

5 0

3 years ago

which of the folloing statements about ionization energy is true? A elements toward the bottom of a group periodic table general

beks73 [17]

<span>
accept the flow of electrons.resist the flow of electrons.accept the flow of protons.resist the flow of protons.It is one of these </span>

6 0

3 years ago

A researcher reports an f-ratio with df = 3, 36 for an independent-measures experiment. how many treatment conditions were compa

user100 [1]

The correct option is B.

There were 4 treatment conditions compared in the experiment.

F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.

The researcher reports an F-ratio where the degrees of freedom = 3, 36.

F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.

For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.

Let the treatments which were involved in the study can be denoted by k.

Let the total number of individuals involved in the study can be taken as N.

Then, the treatments will be having degrees of freedom as,

$df_{treatments}$ = k-1