The force exerted by gravity is:
F = m g
F = 3300 kg * 9.8 m/s^2
F = 32,430 N
The force exerted due to the inclined plane is:
F tractor = 32,430 N * sin 14
<span>F tractor = 7,823.75 N (answer)</span>
The distance between slit and the screen is 1.214m.
To find the answer, we have to know about the width of the central maximum.
<h3>How to find the distance between slit and the screen?</h3>
- It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
- We have the expression for slit width w as,

where, d is the distance between slit and the screen, and a is the slit width.
- Thus, distance between slit and the screen is,

Thus, we can conclude that, the distance between slit and the screen is 1.214m.
Learn more about the width of the central maximum here:
brainly.com/question/13088191
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Solve for "x"
X=force
18/6=x/9
cross multiply
162=6x
x=27
Hope this helps