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sashaice [31]
3 years ago
6

Which is greater 0.26 or 13%

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
7 0

0.26 because when you convert it it becomes 26%

Pepsi [2]3 years ago
3 0

Answer:

0.26 is greater

Step-by-step explanation:

0.26 becomes 26% when converted.

26% is greater than 13%

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Step-by-step explanation:

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Write the equation of the line passing through (2,-3) and parallel to y=4x-9.
maks197457 [2]

Answer:

y = 4x - 11 .

Step-by-step explanation:

The line y = 4x - 9 has a slope of 4 so our line will also contain 4x.

Using the point-slope form of the equation of a line:

y - y1 = m(x - x1)  ,   we have m = 4 and (x1, y1) = (2, -3):

y - -3 = 4(x - 2)

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2 years ago
Multiply and simplify. Assume that all variables are positive.
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Step-by-step explanation:

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5 0
2 years ago
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
2 years ago
What is the explicit formula for the nth term of a(n)=12a(n-1, where the 1st term is .001?
masya89 [10]
\left\{\begin{array}{ccc}a_1=0.001\\a_n=12a_{n-1}\end{array}\right\\\\\boxed{a_n=0.001\cdot12^{n-1}}
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