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3 years ago

5

Please help me?!?!!?!!??!!?!!!

2 answers:

juin [17]3 years ago

8 0

20+60 = 80 but then subtract 36 which = 44. Finally, add 70 and you get 114

hjlf3 years ago

4 0

I'm pretty sure it's 114 miles.

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A local flower shop sells a dozen roses for $12.85.

NNADVOKAT [17]

He owns a flower shop and sells dozens?

3 0

3 years ago

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Please help me with this question

xz_007 [3.2K]

So you want me to write sentences?

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3 years ago

What are the coordinates (x, y) at which the graphs of 3.6x − 2y = 6 and −2.7x + y = 3 intersect? Round to the nearest tenth if

Bas_tet [7]

3.6x - 2y = 6
-2.7x + y = 3.....multiply by 2
----------------
3.6x - 2y = 6
-5.4x + 2y = 6 (result of multiplying by 2)
----------------add
-1.8x = 12
x = 12/-1.8
x = - 6.67 (or -20/3)

3.6x - 2y = 6
3.6(-6.67) - 2y = 6
-24.01 - 2y = 6
-24.01 - 6 = 2y
-30.01 = 2y
-30.01 / 2 = y
-15 = y

solution : (-6.67, -15)

6 0

3 years ago

Solve the inequality 5z+8≥-7

kirza4 [7]

Answer:

z≥−3

Step-by-step explanation:

1 Subtract 88 from both sides.

5z≥−7−8

2 Simplify -7-8−7−8 to -15−15.

5z≥−15

3 Divide both sides by 55.

z≥− 15/5

4 Simplify 15/5 to 3

z≥−3

3 0

3 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

3 years ago

Read 2 more answers