Answer:
See below
Step-by-step explanation:
Since you didn't give an actual quadratic equation and just the standard form equation, I will reduce ax^2+bx+c=0:
(ax+p)(x+q) where p+q=b and pq=c
Answer: 30 minutes
How: 45 minutes divided by 15 math problems equal 3 minutes per math problem. 3 minutes per math problem times 10 math problems equals 30 minutes on 10 math problems.
45/15=3
3*10=30
Answer:
7
Step-by-step explanation:
7+2=9
7 puzzles
7 puzzles
Answer:
The length would be 10ft and the width would be 8ft
Step-by-step explanation:
For the purpose of this, we'll set the width as x. We can then define the length as x + 2 since we know it is 2 ft longer than the width. Now we can use those along with the perimeter formula to solve for the width.
P = 2l + 2w
36 = 2(x + 2) + 2(x)
36 = 2x + 4 + 2x
36 = 4x + 4
32 = 4x
8 = x
Now since we know that the width is 8ft, we can add 2ft to it to get the length, which would be 10ft.
You can figure this out by setting up an equation and make
x= tens digit
y= ones digit
y + 8 =x (tens digit 8 more than ones)
also we know that
y>0
x>0
since the 10s digit and 1s digit cannot be more than one number, we can say
0 < y > 10
0 < x > 10
since x has to be greater than 0 but less than 10, there is only one number that would fit into the equation for y
2 + 8 = 10
(y cannot equal 2 because than x is equal to 10 and it must be less than)
1 + 8 = 9
( y can be 1 since x is less than 10)
so it would be
y= 1
x= 9
the number would be 91
hope this helped!