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DedPeter [7]
3 years ago
11

(2+2)/2x4+16-10x2/2x3=x

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0
(2+2):2x4:16-10x2:2x3=x
4:2x4+16-10x1x3=x
8+16-30=x
-6=x
x=-6

This signing : signifícate division


I help the my answer can help you
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Read 2 more answers
Help solve this math problem please
quester [9]

Answer:

=536870912

Step-by-step explanation:

\frac{\left(2^3\right)^{10}\cdot \:2^{-8}}{2^{-7}}\\\mathrm{Cancel\:}\frac{\left(2^3\right)^{10}\cdot \:2^{-8}}{2^{-7}}:\quad \frac{\left(2^3\right)^{10}}{2}\\\frac{\left(2^3\right)^{10}\cdot \:2^{-8}}{2^{-7}}\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=\frac{1}{x^{b-a}}\\\frac{2^{-8}}{2^{-7}}=\frac{1}{2^{-7-\left(-8\right)}}\\=\frac{\left(2^3\right)^{10}}{2^{-7-\left(-8\right)}}\\\mathrm{Subtract\:the\:numbers:}\:-7-\left(-8\right)=\\=\frac{\left(2^3\right)^{10}}{2}

\mathrm{Simplify\:}\left(2^3\right)^{10}:\quad 2^{30}\\\left(2^3\right)^{10}\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}\\=2^{3\cdot \:10}\\\mathrm{Multiply\:the\:numbers:}\:3\cdot \:10=30\\=2^{30}\\=\frac{2^{30}}{2}\\\mathrm{Cancel\:the\:common\:factor:}\:2\\=2^{29}\\2^{29}=536870912\\=536870912

7 0
4 years ago
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