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4 years ago

PLEASE HELP ME ANSWER THESE I DOMT UNDERSTAND THEM... PLEASE AND THANK YOU

Mathematics

1 answer:

insens350 [35]4 years ago

5 0

Answer:

Step-by-step explanation:

3 $\frac{3}{5ax_{3} }$

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The slope of the line below is -3. Which of the following is the point-slope

Anna [14]

Given:

The slope of the line is -3.

The line passes through the point (2,-2).

To find:

The point-slope form of the line.

Solution:

Point slope form: If a line passes through the point $(x_1,y_1)$ with slope m, then the point-slope form of the line is:

$y-y_1=m(x-x_1)$

The slope of the line is -3 and it passes through the point (2,-2). So, the point-slope form of the line is:

$y-(-2)=-3(x-2)$

$y+2=-3(x-2)$

Therefore, the required point slope form of the given line is $y+2=-3(x-2)$ .

5 0

3 years ago

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x2 + 9x?

inn [45]

Hello :
y = 3x²+9x
= 3(x² + 3x )
= 3 ( x² +2(3/2)x +(3/2)²) -(3/2)²)
= 3((x+3/2)² -9/4)
y = 3 (x+3/2)² -27/4
<span>the x-coordinate of the vertex is : - 3/2</span>

8 0

3 years ago

Read 2 more answers

The area of a rectangular field is 6052 m².

Aleonysh [2.5K]

Answer:

<h2>length = 89 m</h2>

Step-by-step explanation:

Area of a rectangle = l × w

where

l is the length

w is the width

From the question

Area = 6052 m²

width = 68 m

To find the length substitute the values into the above formula

6052 = 68l

Divide both sides by 68

We have the final answer as

<h3>length = 89 m</h3>

Hope this helps you

5 0

3 years ago

Read 2 more answers

3 is less then is equal to 7 +g

Helga [31]

G >\ -4 ( g is greater than or equal to negative 4 )

8 0

3 years ago

What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in

elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

<em><u>Solution:</u></em>

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>

$A = \frac{1}{2} a \sqrt{c^2 - a^2}$

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

$A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}$

$A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727$

Thus area of triangle is 12.727 square inches

5 0

3 years ago