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r-ruslan [8.4K]

3 years ago

7

Write as a fraction or as a mixed number in simplest form 6.025

1 answer:

xz_007 [3.2K]3 years ago

6 0

Dived 25 and 1000 by 5 to get 1/40 add the 6 so its 6 and 1/40

You might be interested in

Select one:<br> a. 4<br> b.5<br> c. 6<br> d. 7

tino4ka555 [31]

Answer:

C

Step-by-step explanation:

Given 2 secants intersect a circle from a point outside the circle, then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 10 + x) = 6(6 + 10 + x)

x(2x + 10) = 6(16 + x) ← distribute parenthesis on both sides

2x² + 10x = 96 + 6x ← subtract 96 + 6x from both sides

2x² + 4x - 96 = 0 ← in standard form

Divide through by 2

x² + 2x - 48 = 0 ← factor the left side

(x + 8)(x - 6) = 0

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 6 = 0 ⇒ x = 6

However x > 0 ⇒ x = 6 → C

7 0

4 years ago

If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),

nikklg [1K]

Step-by-step explanation:

<u>Step 1: Solve using the first point</u>

<em>(2, 28)</em>

$28 = a(2)^3 + b(2)^2 + c(2) + d$

$28 = 8a + 4b + 2c + d$

<u>Step 2: Solve using the second point</u>

<em>(-1, -5)</em>

$-5 = a(-1)^3 + b(-1)^2 + c(-1) + d$

$-5 = -a + b - c + d$

<u>Step 3: Solve using the third point</u>

<em>(4, 220)</em>

$220 = a(4)^3 + b(4)^2 + c(4) + d$

$220 = 64a + 16b + 4c + d$

<u>Step 4: Solve using the fourth point</u>

<em>(-2, -20)</em>

$-20 = a(-2)^3 + b(-2)^2 + c(-2) + d$

$-20 = -8a + 4b - 2c + d$

<u>Step 5: Combine the first and fourth equations</u>

<u /> $28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d$

$8 = 8b + 2d$

$8 - 8b = 8b - 8b + 2d$

$(8 -8b)/2 = 2d/2$

$4 - 4b = d$

<u>Step 6: Solve for c in the second equation</u>

$-5 + 5 = -a + b - c + d + 5$

$0 + c = -a + b - c + c + d + 5$

$c = -a + b + d + 5$

<u>Step 7: Substitute d with the stuff we got in step 5</u>

$c = -a + b + (4 - 4b) + 5$

$c = -a + b + 4 - 4b + 5$

$c = -a - 3b + 9$

<u>Step 8: Substitute d and c into the first equation</u>

<u /> $28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)$

$28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b$

$28 - 22 = 6a - 6b + 22 - 22$

$6 / 6 = (6a - 6b) / 6$

$1 + b = a - b + b$

$1 + b = a$

<u>Step 9: Substitute a, b, and c into the third equation</u>

$220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)$

$220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b$

$220 - 100 = 60b + 100 - 100$

$120 / 60 = 60b / 60$

$2 = b$

<u>Step 10: Find a using b = 2</u>

$a = b + 1$

$a = (2) + 1$

$a = 3$

<u>Step 11: Find c using a = 3 and b = 2</u>

$c = -a - 3b + 9$

$c = -(3) - 3(2) + 9$

$c = -3 - 6 + 9$

$c = 0$

<u>Step 12: Find d using b = 2</u>

$d = 4 - 4b$

$d = 4 - 4(2)$

$d = 4 - 8$

$d = -4$

Answer: $a = 3, b = 2, c = 0,d = -4$

6 0

3 years ago

Read 2 more answers

25% of what nember is 19

attashe74 [19]

You would do 0.25x (x is the unknown total number)=19. It is because of is a multiply sign, so 0.25*x=19. Divide both sides by 0.25 and you get 76 as your answer.

6 0

3 years ago

Read 2 more answers

Find the LCM and HCF of 15, 42 and 123

skelet666 [1.2K]

Answer:

LCM - 1

HCF - 3

Step-by-step explanation:

LCM - Lowest Common Factors

HCF - Highest Common Factors

____________________________________________________________

Factors of 15 - 1, 3, 5, 15

Factors of 42 - 1, 2, 3, 6, 7, 14, 21, 42

Factors of 123 - 1, 3, 41, 123

So now we know the factors of 15, 42, 123 what is lowest and highest factor we can find in every number

____________________________________________________________

I have bolded the lowest and highest common factor.

Factors of 15 - 1, 3, 5, 15

Factors of 42 - 1, 2, 3, 6, 7, 14, 21, 42

Factors of 123 - 1, 3, 41, 123

_______________________________________________

LCM - 1

HCF - 3

7 0

3 years ago

What is the median of 16, 20, 20, 23, 25, 27, 29, 31, 31, and 32.

seraphim [82]

Answer:

27

Step-by-step explanation:

The madian is gis

5 0

3 years ago