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3 years ago

99-4-2-22-2-3-4--4--3-2-3-4-5-6-6-3-3-2-3-4--5-6-5-4-

Mathematics

1 answer:

zvonat [6]3 years ago

7 0

Answer:

REASON: You just do the maths.

When you have the double subtraction sign infront of the 4, 3, and 5 I'm going to take it as if it's a negative.

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Use the function f (x) = -2x4 + 3x) – 4x+ 9x2 + 2x – 5 to complete these sentences.

Mekhanik [1.2K]

Answer:

srry need ko den tan

Step-by-step explanation:

pa brainly mo nalang

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2 years ago

For the data in the table, tell whether y varies directly with x. If it does, write an equation for the direct variation.

allochka39001 [22]

It is direct variation if x/y is a constant.

x/y = 2 / -6.6 = -1/3.3

y/x = -9.9/3 = -3.3

y/x = -6.6/ 2 = -3.3

y/x = -13.2/ 3 = -3.3

y/x = -16.2/ 3 = -3.24

So its not exactly direct variation as the last values is slightly different from the first 3.

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3 years ago

Someone please tell me the answer

Schach [20]

Answer:

3¹²

Step-by-step explanation:

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3 years ago

Suppose a candidate for public office is favored by only 48% of the voters. if a sample survey randomly selects 2500 voters, the

Drupady [299]

Mean=0.48
standard deviation=0.01
thus using the z-score:
P(x>0.5) we shall have the following:
z=(0.5-0.48)/0.01=2
thus
P(x>0.5)
=1-P(x<0.5)
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7 0

3 years ago

A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w

AfilCa [17]

Answer:

$\frac{15}{4802}$ , $\frac{15}{9604}$ , $\frac{9}{2401}$ , $\frac{9}{4802}$

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: $\frac{4}{14}$

green: $\frac{2}{14}$

yellow: $\frac{3}{14}$

blue: $\frac{5}{14}$

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = $\frac{3}{14} \cdot \frac{4}{14} \cdot \frac{2}{14} \cdot \frac{5}{14} =\frac{15}{4802}$

Removing 1 blue, 1 green, 1 green, and 1 yellow = $\frac{5}{14} \cdot \frac{2}{14} \cdot \frac{2}{14} \cdot \frac{3}{14} =\frac{15}{9604}$

Removing 1 red, 1 red, 1 yellow, and 1 yellow = $\frac{4}{14} \cdot \frac{4}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} =\frac{9}{2401}$

Removing 1 green, 1 yellow, 1 yellow, and 1 red = $\frac{2}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} \cdot \frac{4}{14} =\frac{9}{4802}$

4 0

2 years ago