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denis-greek [22]
3 years ago
11

9. What is composition? Why is composition important?

Computers and Technology
1 answer:
Veronika [31]3 years ago
4 0
Composition- a work of music, literature, or art

This is important because art helps people express oneself
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My friend Leo wants to have an emergency plan for his final exams on University of Southern Algorithmville. He has N subjects to
Brut [27]

Answer:

Greedy algorithm

Explanation:

Greedy is an algorithmic paradigm that builds up a solution piece by piece, always choosing the next piece that offers the most obvious and immediate benefit. Greedy algorithms are used for optimization problems. An optimization problem can be solved using Greedy if the problem has the following property: At every step, we can make a choice that looks best at the moment, and we get the optimal solution of the complete problem.

If a Greedy Algorithm can solve a problem, then it generally becomes the best method to solve that problem as the Greedy algorithms are in general more efficient than other techniques like Dynamic Programming. But Greedy algorithms cannot always be applied. For example, the Fractional Knapsack problem (See this) can be solved using Greedy, but 0-1 Knapsack cannot be solved using Greedy.

The following are some standard algorithms that are Greedy algorithms.

1) Kruskal’s Minimum Spanning Tree (MST):

In Kruskal’s algorithm, we create an MST by picking edges one by one. The Greedy Choice is to pick the smallest weight edge that doesn’t cause a cycle in the MST constructed so far.

2) Prim’s Minimum Spanning Tree:

In Prim’s algorithm also, we create an MST by picking edges one by one. We maintain two sets: a set of the vertices already included in MST and the set of the vertices not yet included. The Greedy Choice is to pick the smallest weight edge that connects the two sets.

3) Dijkstra’s Shortest Path:

Dijkstra’s algorithm is very similar to Prim’s algorithm. The shortest-path tree is built up, edge by edge. We maintain two sets: a set of the vertices already included in the tree and the set of the vertices not yet included. The Greedy Choice is to pick the edge that connects the two sets and is on the smallest weight path from source to the set that contains not yet included vertices.

4) Huffman Coding:

Huffman Coding is a loss-less compression technique. It assigns variable-length bit codes to different characters. The Greedy Choice is to assign the least bit length code to the most frequent character.

The greedy algorithms are sometimes also used to get an approximation for Hard optimization problems. For example, the Traveling Salesman Problem is an NP-Hard problem. A Greedy choice for this problem is to pick the nearest unvisited city from the current city at every step. These solutions don’t always produce the best optimal solution but can be used to get an approximately optimal solution.

8 0
3 years ago
JAVA
shusha [124]

public class JavaApplication64 {

   

   public static void main(String[] args) {

       int count = 0;

       for (int i = 23; i <= 89; i++){

           if (count == 10){

               System.out.println("");

               count = 0;

           }

           System.out.print(i+" ");

           count += 1;

       }

   }

   

}

I hope this helps!

5 0
3 years ago
How are the internet and the World Wide Web different from each other
jeka94

The terms Internet and World Wide Web are often used interchangeably in everyday speech; it is common to speak it as " going on the Internet " when using a web browser to view web pages. However, the World Wide Web is only one of a large number of Internet services.

4 0
3 years ago
Given a sorted list of integers, output the middle integer. A negative number indicates the end of the input (the negative numbe
masya89 [10]

Answer:

The program in Python is as follows:

myList = []

num = int(input())

count = 0

while num>=0:

   myList.append(num)

   count+=1

   num = int(input())

myList.sort()

mid = int((count-1)/2)

print(myList[mid])

Explanation:

This initializes the list

myList = []

This gets the first input

num = int(input())

This initializes count to 0

count = 0

The following is repeated until the user inputs a negative number

while num>=0:

This appends the input number to the list

   myList.append(num)

This increments count by 1

   count+=1

This gets another input

   num = int(input())

This sorts the list

myList.sort()

Assume the number of inputs is odd, the middle element is calculated as

mid = int((count-1)/2)

This prints the middle element

print(myList[mid])

<em>From the complete question. the condition that ends the loop is a negative integer input</em>

8 0
3 years ago
Vẽ sơ đồ lắp đặt gồm 2 cầu chì, 1 ổ điện, 2 cực điều khiển 2 đèn mắc song song
Nookie1986 [14]

Answer:

okokikhjhghjjjkkkkkokoloo

7 0
3 years ago
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