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3 years ago

How much must an object weigh to be able to float in water

Physics

2 answers:

dolphi86 [110]3 years ago

7 0

Answer:

Explanation:

Vaselesa [24]3 years ago

4 0

Answer: The answer to how much must an object weigh to be able to float in water is (B) less than the amount of water it displaces.

Explanation:

I hope this helped (:

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Mnenie [13.5K]

Answer:

$T_0=80695.17162...$

Explanation:

Given equation:

$\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124$

To solve the given equation:

$\textsf{Apply log rules}: \quad e^{\ln (x)}=x$

$\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}$

Multiply both sides by T₀:

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$\implies T_0=T_0e^{-0.00124}+100$

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$\implies T_0-T_0e^{-0.00124}=100$

Factor out the common term T₀:

$\implies T_0(1-e^{-0.00124})=100$

Divide both sides by $(1-e^{-0.00124})$

$\implies T_0=\dfrac{100}{1-e^{-0.00124}}$

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$\implies T_0=\dfrac{100}{1-0.99876...}$

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3 years ago

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Answer:

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