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mojhsa [17]
3 years ago
9

One sprinter has a stride of 120cm, another 75cm. How many steps do they each take if they run a 100m race?

Physics
1 answer:
coldgirl [10]3 years ago
3 0

Explanation:

100 m / (1.20 m) = 83.3

100 m / (0.75 m) = 133.3

Rounded up, the first sprinter takes 84 steps, and the second sprinter takes 134 steps.

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A planet outside of our solar system
Zolol [24]

Answer:

exoplanets is any planet beyond our solar system.

4 0
3 years ago
Some elements are more reactive than other elements why do you think this is
EastWind [94]

Answer:

Different elements all have different amounts of electrons in there outter shell.

Explanation

If you look at a periodic table, the elements are all listed in "Groups" up at the top you'll see the numbers, or columns. Each column's number represent how many electrons there are in each particular element.

hope this makes sense....

8 0
3 years ago
A cart is pushed at a supermarket for a distance of 30 m South, then 15 m West and finally 5 m West. This entire motion lasts fo
PSYCHO15rus [73]

the speed would have to be somewhere between 1.667 or 1.666 miles per minute.

add 30, 15, 5 together and you will get 50

50 is the total miles traveled

then you multiply 30 by 1.666 and you will get 49.98 but it's still not quite 50 miles

if you multiply 30 by 1.667 and you will get 50.01 but its a little over to miles

i got the 30 from the minutes traveled

anyway that's the best i got for speed

3 0
3 years ago
Read 2 more answers
Please show the work and steps. The answer is (3.3 s, 15 m/s)
Anna [14]

Answer:

t = 3.3 s and V = 15 m/s

Explanation:

Given that,

Distance covered by the car, d = 50 m

Initial speed, u = 5 m/s

Final speed, v = 25 m/s

Firstly we can find the acceleration of the car using third equation of motion. i.e.

v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(5)^2}{2(50)}\\\\a=6\ m/s^2

Let t is the time taken by the car to occur this.

t=\dfrac{v-u}{a}\\\\t=\dfrac{25-5}{6}\\\\t=3.3\ s

Let v is the average velocity of the car. It can be calculated as follows :

V=\dfrac{u+v}{2}\\\\V=\dfrac{25+5}{2}\\\\V=\dfrac{30}{2}\\\\V=15\ m/s

So, the time taken by the car to occur this is 3.3 seconds and the average velocity of the car is 15 m/s.

8 0
3 years ago
For hydrogen gas, H2, tables give values for the parame ters of eqn 7a of a-2728JKmoll, b-3.26x 10 3JK-2 mor and c- 0.50 J K2 mo
Anestetic [448]

Answer:

27.32 J/k Mole.

Explanation:

The constant pressure heat capacity of hydrogen is given by Shomate equation

C_p= a + b×t + c×t^2

C_p = heat capacity (J/mol*K)

t = temperature (K) / 1000.

Temperature =25°C=298 K

t= 298/1000 =0.298

putting values we get

C_p = 27.28+3.26x10^-3 ×0.298+0.50×(0.298)^2

C_p=27.32 J / K mole

the value of the constant pressure heat capacity of hydrogen at 25 °C=

C_p=27.32 J / K mole

5 0
3 years ago
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