Answer:
The ladder is moving at the rate of 0.65 ft/s
Explanation:
A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the wall.
The attached figure shows whole description such that,
.........(1)

We need to find,
at x = 5 ft
Differentiating equation (1) wrt t as :



Since, 

At x = 5 ft,


So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.
Answer:The highest possible efficiency of this heat engine is 11%
Explanation:
Saturated water temperature at P1, Pressure in Heat addition,
1.1 MPa=185°C +273= 458K
Saturated water temperature at P2, Pressure in Heat rejection,
0.3MPa=133.5°C+ 273=406.5K
The highest possible efficiency of any heat engine is the Carnot efficiency given as
Carnot efficiency, ηmax = 1- (T2/ T1)
1- (406.5K/458K)
1-0.88755=0.112
=11%
Answer:
Frick is pushing harder
Explanation:
if Frack weighs more and he was pushing harder they would be moving, but if Frick pushes harder then they wont move
The attraction will decrease. Hope I helped :)
Answer:
It is direct proportionality. The greater the mass, the greater is the gravitational potential energy. The equation for GPE is : GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height above the ground. As you can see GPE is directly proportional to mass, and height. KT.
Explanation:
Gravitational potential energy is a function of both the mass of your system and the mass of the thing generating the gravity field around your system.
The relationship is linear, which means that if you multiply or divide one of the masses by some number but leave everything else the same, you multiply or divide the potential energy by the same number. A 3kg mass has three times the gravitation potential energy of a 1kg mass, if placed in the same location.