The answer is A you need to multiply the number of buquets then add it to thr price of the vase
Answer:
x-3y <u>></u> 5
step-by-step explanation:
Answer:
Step-by-step explanation:
Givens
Length = a
Width = a + 3
Formulas
P = 2L + 2w
Area = L * w
Solution
Perimeter
P = 2L + 2w
P = 2*a + 2(a + 3) Remove the Brackets
p = 2a + 2a + 6 Combine
<u><em>P = 4a + 6</em></u>
Area
Area = L * w
Area = a (a + 3)
<u><em>Area = a^2 + 3a</em></u>
You can solve this either just plain algebra or with the use of trigonometry.
In this case, we'll just use algebra.
So, if we let M be the the point that partitions the segment into a ratio of 3:2, we have this relation:
KM/ML = 3/2
KM = 1.5 ML
We also have this:
KL = KM + ML
Substituting KM,
KL = (3/2) ML + ML
KL = 2.5 ML
Using the distance formula and the given coordinates of the K and L, we get the length of KL
KL = sqrt ( (5-(-5)^2 + (1-(-4))^2 ) = 5 sqrt(5)
Since,
KL = 2.5 ML
Substituting KL,
ML = (1/2.5) KL = (1/2.5) 5 sqrt(5) = 2 sqrt(5)
Using again the distance formula from M to L and letting (x,y) as the coordinates of the point M
ML = 2 sqrt(5) = sqrt ( (5-x)^2 + (1-y)^2 ) [let this be equation 1]
In order to solve this, we need to find an expression of y in terms of x. We can use the equation of the line KL.
The slope m is:
m = (1-(-4))/(5-(-5) = 0.5
Using the general form of the linear equation:
y = mx +b
We substitue m and the coordinate of K or L. We'll just use K.
-5 = (0.5)(-4) + b
b = -1.5
So equation of the line is
y = 0.5x - 1.5 [let this be equation 2]
Substitute equation 2 to equation 1 and solving for x, we get 2 values of x,
x=1, x=9
Since 9 does not make sense (it does not lie on the line), we choose x=1.
Using the equation of the line, we get y which is -1.
So, we get the coordinates of point M which is (1,-1)
Area of a triangle:
A (triangle )= 4 · 6 / 2 = 12 ft²
150 - 12 = 138 ft² ( the maximum area of the rectangle )
L = ?
W = 6 ft
A ( rectangle ) = L · W
L · 6 = 138
L = 138 : 6 = 23 ft.
Answer: the maximum length of the base of the rectangle he can build is 23 ft.
