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2 years ago

The quadratic function below has an axis of symmetry through x = -4; a vertex at (-4, -9) and zeroes at x = -7 and x = 0.

Mathematics

1 answer:

Pavlova-9 [17]2 years ago

4 0

Answer:

True

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 9), thus

y = a(x + 4)² - 9

To find a substitute the coordinates of the zero (- 7, 0) into the equation.

0 = a(- 7 + 4)² - 9, that is

0 = 9a - 9 ( add 9 to both sides )

9a = 9 ( divide both sides by 9 )

a = 1, thus

y = (x + 4)² - 9 ← expand factor using FOIL

y = x² + 8x + 16 - 9

y = x² + 8x + 7

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An acute triangle has two sides measuring 8 cm and 10 cm . What is the best representation of the possible range of values for t

Mekhanik [1.2K]

Answer:

the right answer is 2 < s< 18

Step-by-step explanation:

The Third side of the triangle must be greater than the difference of the other two sides which is 10 -8= 2 and smaller than the sum of the other two sides of the triangle which is 10+8= 18.

so third side should be greater than 2 and less than 18.

So right answer is 2 < s< 18

5 0

2 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

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2 years ago

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omeli [17]

The angle of the triangle would be 72

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2 years ago

Why do the probability of an event and the probability of its complement add up to 1

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3 years ago

Devaughn is 6 years younger than Sydney. The sum of their ages is 50 . What is Sydney's age?

dedylja [7]

Sydney is 44 years old.
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3 years ago