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kenny6666 [7]
3 years ago
9

The quadratic function below has an axis of symmetry through x = -4; a vertex at (-4, -9) and zeroes at x = -7 and x = 0.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

True

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 9), thus

y = a(x + 4)² - 9

To find a substitute the coordinates of the zero (- 7, 0) into the equation.

0 = a(- 7 + 4)² - 9, that is

0 = 9a - 9 ( add 9 to both sides )

9a = 9 ( divide both sides by 9 )

a = 1, thus

y = (x + 4)² - 9 ← expand factor using FOIL

y = x² + 8x + 16 - 9

y = x² + 8x + 7

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Find the positive value of x if: 5^(x^2 - 2x) = 1
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From the given figure,write the corresponding angle of puv​
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Step-by-step explanation:

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Find the surface area of the triangular prism. The base of the prism is an isosceles triangle. The answer is _ cm^2
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3 years ago
If the endpoint is (3/2, 1 1/2), and the midpoint is (2/5, -8/5) what is the other endpoint
alukav5142 [94]

Answer:

The answer to your question is  ( -7/10, -4 7/10)

Step-by-step explanation:

Data

Enpoint (3/2, 1 1/2)                  x1 = 3/2     y1 = 1 1/2

Midpoint (2/5, -8/5)                xm = 2/5    ym = -8/5

Entpoint 2 ( x, y)

Formula

Xm = (x1 + x2)/2    Solve for x2    x2 = 2xm - x1

Ym = (y1 + y2)/2     Solve for y2   y2 = 2ym - y1

Substitution

                  x2 = 2(2/5) - 3/2

                  x2 = 4/5 - 3/2

                  x2 = (8 - 15)/10

                 x2 = -7/10

                  y2 = 2(-8/5) - 1 1/2

                 y2 = -16/5 - 3/2

                 y2 = (-32 - 15) / 10

                y2 = -47/10 = -4 7/10

5 0
3 years ago
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