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3 years ago

Can someone help me?

Mathematics

1 answer:

iren2701 [21]3 years ago

3 0

Answer:

A. congruent -SSS

Step-by-step explanation:

Picture below

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ANSWER THIS MATH QUESTION

shusha [124]

Answer:

<h2>The slope of the line tangent to the function at x = 1 is 2.01 ≅2.</h2>

Step-by-step explanation:

Using the formula of derivative, it can be easily shown that, $\frac{d f(x)}{dx} = 2$ where $f(x) = x^{2}$ .

Here we need to show that as per the instructions in the given table.

Δy = f(x + Δx) - f(x) = f(1 + 0.01) - f(1) = $(1 + 0.01)^{2} - 1^{2} = 0.0201$ .

In the above equation, we have put x = 1 because we need to find the slope of the line tangent at x = 1.

Hence, dividing Δy by Δx, we get, $\frac{0.0201}{0.01} = 2.01$ .

Let's examine this taking a smaller value.

If we take Δx = 0.001, then Δy = $1.001^{2} - 1^{2} = 0.002001$ .

Thus, $\frac{0.002001}{0.001} = 2.001$ .

The more smaller value of Δx is taken, the slope of the tangent will be approach towards the value of 2.

5 0

3 years ago

What are the best strategies to compare fractions. Name as many strategies as you want.

inn [45]

Common denominator
Common multiple
Simplest Form
GCF: Greatest Common Factor
LCM: Least Common Factor
Then Comparing Plain

4 0

3 years ago

Read 2 more answers

Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant

Alex787 [66]

Find the intercepts for both planes.

Plane 1, x + y + 2z = 2:

$y=z=0\implies x=2\implies (2,0,0)$

$x=z=0\implies y=2\implies(0,2,0)$

$x=y=0\implies 2z=2\implies z=1\implies(0,0,1)$

Plane 2, 4x + 4y + z = 8:

$y=z=0\implies4x=8\implies x=2\implies(2,0,0)$

$x=z=0\implies4y=8\impliesy=2\implies(0,2,0)$

$x=y=0\implies z=8\implies(0,0,8)$

Both planes share the same x- and y-intercepts, but the second plane's z-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (x, y)-plane where z = 0, we see the bounded region projects down to the triangle in the first quadrant with legs x = 0, y = 0, and x + y = 2, or y = 2 - x.

So the volume of the region is

$\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx$