Answer:
Step-by-step explanation:
follow the Pemdas order of operations
add and subtract (left to right)
apply the rule +(-a)=-a
+(-78)=-78
=54-78-(-39)
54-78=-24
=-24-(-39)
apply the rule -(-a)=+a
-(-39) =+39
=-24 +39
-24+39=15
=15
Answer:
b
Step-by-step explanation:
1. You have the following quadratic equation and to solve it, you must follow the steps below:
<span>
x</span>²<span>+3=9x
2. The form of the equation that you need to apply the quadratic formula, is:
ax</span>²+bx+c=0
<span>
3. Then:
</span>
x²<span>+3=9x
</span> x²-9x<span>+3=0
</span><span>
4. The quadratic formula is shown below:
x=(-b±√(b^2-4ac))/2a
5. Then, you have:
a=1
b=-9
c=3
6. When you substitute the values into the quadratic formula, you obtain:
x1=0.34
x2=8.65</span>
The question is about types and number of soultions so you must use b^2-4ac which is the experssion under the root in the quadratic formula
so
if
b^2-4ac=0 then there is one real soultion
if
b^2-4ac<0 then there are two imaginary soultions that differ in the sign between them
if
b^2-4ac>0 then there are two real soultions
so a polynomial is written in the form
ax^2+bx+c=0
so a=-4
b=-4
c=-1
so b^2-4ac=16-16=0
so one real soultion is the answer you are looking
type:real
number:1
Answer:

Step-by-step explanation:
To calculate the result of that mutiplication you have to firs evaluate the first term of the second function multipying the whole first function, woudl be like this:

Now that you have this, you multiply the second term from the second function to obtain:

Now you just have to add both results:

+ 
And the result of the sum would be:
