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3 years ago

7.5 rounded to the nearest tenth

Mathematics

2 answers:

DIA [1.3K]3 years ago

6 0

Answer: 7.5

Step-by-step explanation: It has no 100th so its 7.5

aleksley [76]3 years ago

4 0

Answer:

7.5

Step-by-step explanation:

this is already rounded to the tenths place if there was a number in the hundreds place then you would need tor round it

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3. In the month of August, a car dealership sold a total of 72

Elan Coil [88]

Answer:

<em>The dealership sold in August 24 trucks and 48 cars</em>

Step-by-step explanation:

Equations

A dealership reported they sold a total of 72 vehicles.

It also determined that for every 4 cars sold, they sold 2 trucks. It means that they sold twice as many cars as trucks.

Let x be the number of trucks sold.

It follows that 2x is the number of cars sold.

The sum of both numbers must equal 72:

x + 2x = 72

Simplifying:

3x = 72

Solving:

x = 72 / 3 = 24

The number of cars were

2x= 48

The dealership sold in August 24 trucks and 48 cars

7 0

3 years ago

April mails 3 packages.

IRISSAK [1]

I got the same answer you did. I think it’s right hope this helps!

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3 years ago

What is the sum os the interior angles of the polygon?

RSB [31]

To find the suum the formula is (n - 2) x 180 degrees

4 0

4 years ago

If 8y-8=24, find the value of 2y

algol [13]

8 is the answer
for 2y

6 0

3 years ago

Read 2 more answers

Which trigonometric ratios are correct for triangle ABC? Check all that apply

sergij07 [2.7K]

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and
HYP denote the hypotenuse.

then:

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ

Back to our problem,

using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
$

$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
$Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}$

Answer: 1, 3, 4

5 0

3 years ago