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DanielleElmas [232]
3 years ago
15

Find the real solutions of e^3t=100

Mathematics
1 answer:
wel3 years ago
4 0
E^3t=100

ln100=3t

t=(ln100)/3
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A leopard runs 0.25 miles at an average speed of 40mph
rusak2 [61]

Answer:

True

Explanation

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3 years ago
The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.
Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = \frac{b}{a}

- This is a vertical hyperbola, the equation is

       \frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1

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a is the distance from the center to the vertex = 4

b = 2(4) = 8

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       \frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1

7 0
3 years ago
Read 2 more answers
Graph the system of equations. Then determine whether the system has no solution, one solution, or infinitely many solutions. If
pav-90 [236]

Answer:

Second option: One solution. Independent.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Since the equations of the system have this form, we know that they are lines.

We can identify that the y-intercept of the first equation y=-5x+1 is:

b=1

Now we need to find the x-intercept. Substitute y=0 and solve for "x":

0=-5x+1\\\\5x=1\\\\x=\frac{1}{5}=0.2

Then, we can graph the first line which passess through the points (0,1) and (0.2,0). Observe the graph attached.

The y-intercept of the second equation y=-2x-2 is:

b=-2

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0=-2x-2\\\\2x=-2\\\\x=\frac{-2}{2}=-1

Then, we can graph the second line, which passess through the points (0,-2) and (-1,0).

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4 0
3 years ago
10 x 4 thousands in unit form
Sindrei [870]

Answer:

Step-by-step explanation:

Simplify.

10 x 4000

40000

Unit form.

forty-thousand = four thousands

I'm sorry if I misunderstood.

Please add Brainliest if you'd like, not that it matters.

3 0
3 years ago
Rod is saving Php2000 in a bank at the end of each month which gives an interest of 1% compounded monthly.How much is the saving
agasfer [191]

Answer:

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Step-by-step explanation:

Given

P = 2000 --- Principal

r = 1\% --- Rate

t = 2\ years --- Time

n = 12 --- monthly

Required

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This is calculated as:

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So, we have:

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A = 2000(1 + \frac{1}{100*12})^{24}

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A = 2000(\frac{1200+1}{1200})^{24}

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A = 2000*1.02019

A = 2040.38

<em>Hence, the final amount is: Php2040.38</em>

7 0
3 years ago
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