What's 9 million in standard form

Mathematics

2 answers:

wariber [46]3 years ago

6 0

The answer is 9,000,000

MariettaO [177]3 years ago

6 0

9 million in standard form is <span>9,000,000</span>

You might be interested in

Solve the equation 6n -5 + 5n = 15 + n -4 + 8n

timurjin [86]

Answer:

if your solving for n.....

Step-by-step explanation:

n=3

7 0

3 years ago

Read 2 more answers

Tickets to a school play are $4.50 for an adult and $3.00 for a student. If 300 tickets are sold and $1087.50 collected, how man

Kryger [21]

Answer:

<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>

Step-by-step explanation:

$a-\text{number of the tickets for an adult}\\s-\text{number of the tickets for a student}\\\\(1)\qquad a+s=300\\(2)\qquad4.5a+3s=1087.5\\------------\\(1)\\a+s=300\qquad\text{subtstitute}\ s\ \text{from both sides}\\a=300-s\\\\\text{Put it to (2):}\\\\4.5(300-s)+3s=1087.5\qquad\text{use distributive property}\\\\(4.5)(300)+(4.5)(-s)+3s=1087.5\\\\1350-4.5s+3s=1087.5\qquad\text{subtract 1350 from both sides}\\\\-1.5s=-262.5\qquad\text{divide both sides by (-1.5)}\\\\\boxed{s=175}$

$\text{Put the value of}\ s\ \text{to (1):}\\\\a=300-175\\\\\boxed{a=125}$

3 0

3 years ago

Consider the given function and the given interval. f$x$ = (x - 7)**2 text(, ) [5 text(, ) 11] (a) Find the average value fave

Jet001 [13]

a. $f$ has an average value on [5, 11] of

$f_{\rm ave}=\displaystyle\frac1{11-5}\int_5^{11}(x-7)^2\,\mathrm dx=\frac{(x-7)^3}{18}\bigg|_5^{11}=\frac{4^3-(-2)^3}{18}=4$

b. The mean value theorem guarantees the existence of $c\in(5,11)$ such that $f(c)=f_{\rm ave}$ . This happens for

$(c-7)^2=4\implies c-7=\pm2\implies c=9\text{ or }c=5$

8 0

3 years ago

Find the angle of depression from the top of a lighthouse, 260 feet above water to a ship that's 270 feet offshore?

expeople1 [14]

Answer: OPTION C.

Step-by-step explanation:

Observe the triangle ABC attached.

Notice that the angle of depression is represented with $\alpha$ .

Knowing that the top of a lighthouse is 260 feet above water and the ship is 270 feet offshore, you can find the value of $\alpha$ by using arctangent:

$\alpha= arctan(\frac{opposite}{adjacent})$